Convert raw query to Laravel eloquent

2019-02-25 19:03发布

How to convert this raw query to Laravel eloquent way:

select c.name as country from country c, address ad, city ci where
ad.id = 1 and city.id = ad.city_id and c.code = ci.country_code

2条回答
Lonely孤独者°
2楼-- · 2019-02-25 19:14

First link

Second link

Query Builder

DB::table("country")
->join('city', 'city.country_code', '=', 'country.user_id')
->join('address', 'address.city_id', '=', 'city.id')
->select('country.name as country')
->where('address.id', 1)
->get();

Eloquent

Country::with(['city','address' => function($query){
    return $query->where('id', 1)
}])
->select('country.name as country')
->get();
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Melony?
3楼-- · 2019-02-25 19:19

I will modify the answer from Andrey Lutscevich eloquent part

Country::select('country.name as country')->has('city')
  ->whereHas('address', function ($query)
  {
    $query->where('id', 1);
  })
  ->get();

Querying Relationship Existence When accessing the records for a model, you may wish to limit your results based on the existence of a relationship use has in that case

WhereHas methods put "where" conditions on your has queries

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