Random string generation with upper case letters a

Question

I want to generate a string of size N.

It should be made up of numbers and uppercase English letters such as:

• 6U1S75
• 4Z4UKK
• U911K4

How can I achieve this in a pythonic way?

Answer 1

You can use the code

var chars = "ABC123";
        var random = new Random();
        var result = new string(
            Enumerable.Repeat(chars, 7) //Change 7 to any number of characters you want in your outcome
                      .Select(s => s[random.Next(s.Length)])
                      .ToArray());

        textBox1.Text = result;

This will random spit out a random 7 alphanumeric pattern, simply change the 7 to any number you wish and it will produce that many numbers and/or letters.

Another way to write this is as follows...

var chars = "ABC123";
var stringChars = new char[7]; //Change 7 to any number of characters you want in your outcome
var random = new Random();

for (int i = 0; i < stringChars.Length; i++)
{

stringChars[i] = chars[random.Next(chars.Length)];

}

var finalString = new String(stringChars);

textBox1.Text = finalstring;`

I am unsure of how to add restrictions such as making it to where it does not allow certain numbers and/or letters to be next to each other or repeat such as getting "AAA123" if anyone knows how to restrict the outcome to have something like this please comment back

Answer 2

Based on another Stack Overflow answer, Most lightweight way to create a random string and a random hexadecimal number, a better version than the accepted answer would be:

('%06x' % random.randrange(16**6)).upper()

much faster.

Answer 3

for python 3 import string, random

''.join(random.choice(string.ascii_lowercase + string.ascii_uppercase + string.digits) for _ in range(15))