How to define a circle shape in an Android xml dra

Question

I have some problems finding the documentation of the definitions of shapes in XML for Android. I would like to define a simple circle filled with a solid color in an XML File to include it into my layout files.

Sadly the Documentation on android.com does not cover the XML attributes of the Shape classes. I think I should use an ArcShape to draw a circle but there is no explanation on how to set the size, the color, or the angle needed to make a circle out of an Arc.

Answer 1

Here's a simple circle_background.xml for pre-material:

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:state_pressed="true">
        <shape android:shape="oval">
            <solid android:color="@color/color_accent_dark" />
        </shape>
    </item>
    <item>
        <shape android:shape="oval">
            <solid android:color="@color/color_accent" />
        </shape>
    </item>
</selector>

You can use with the attribute 'android:background="@drawable/circle_background" in your button's layout definition

Answer 2

Just use

ShapeDrawable circle = new ShapeDrawable( new  OvalShape() );

Answer 3

Set this as your view background

<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="oval">
    <stroke
        android:width="1dp"
        android:color="#78d9ff"/>
</shape>

For solid circle use:

<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="oval">
    <solid
        android:color="#48b3ff"/>
</shape>

Solid with stroke:

<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="oval">
    <solid android:color="#199fff"/>
    <stroke
        android:width="2dp"
        android:color="#444444"/>
</shape>

Note: To make the oval shape appear as a circle, in these examples, either your view that you are using this shape as its background should be a square or you have to set the height and width properties of the shape tag to an equal value.

Answer 4

<?xml version="1.0" encoding="utf-8"?>
<shape 
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="oval">

    <stroke
        android:width="10dp"
        android:color="@color/white"/>

    <gradient
        android:startColor="@color/red"
        android:centerColor="@color/red"
        android:endColor="@color/red"
        android:angle="270"/>

    <size 
        android:width="250dp" 
        android:height="250dp"/>
</shape>

Answer 5

Look in the Android SDK samples. There are several examples in the ApiDemos project:

/ApiDemos/res/drawable/

• black_box.xml
• shape_5.xml
• etc

It will look something like this for a circle with a gradient fill:

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="oval" >
    <gradient android:startColor="#FFFF0000" android:endColor="#80FF00FF"
            android:angle="270"/>
</shape>

Answer 6

You can use VectorDrawable as below :

<?xml version="1.0" encoding="utf-8"?>
<vector xmlns:android="http://schemas.android.com/apk/res/android"
    android:width="200dp"
    android:height="200dp"
    android:viewportHeight="64"
    android:viewportWidth="64">

    <path
        android:fillColor="#ff00ff"
        android:pathData="M22,32
        A10,10 0 1,1 42,32
        A10,10 0 1,1 22,32 Z" />
</vector>

The above xml renders as :