Subqueries in CakePHP 3?

2019-02-24 23:58发布

I have two tables products and product_categories that are associated through a third table, products_categories_products, according to CakePHP BelongsToMany conventions (Edit: these associations are established in ProductsTable.php and ProductCategoriesTable.php). I want to generate a list of product categories, using the image from the best selling products to represent each category.

I can achieve my desired outcome using the following function:

public function findImages(Query $query, array $options) {
    $query->select([
        'ProductCategories.id',
        'ProductCategories.name',
        'ProductCategories__image' => '(SELECT Products.image
        FROM product_categories_products AS ProductCategoriesProducts
        LEFT JOIN products AS Products
        ON ProductCategoriesProducts.product_id = Products.id
        WHERE ProductCategoriesProducts.product_category_id = ProductCategories.id
        ORDER BY Products.turnover DESC
        LIMIT 1)'
    ])->where([
        'ProductCategories.name <>' => 'Unsorted'
    ])->order([
        'ProductCategories.name'    => 'asc'
    ]);
    return $query;
}

Is this acceptable or is there a Cake-ier way to achieve my goal? I couldn't really find anything on the topic of crafting subqueries in CakePHP 3. I just stumbled into the above solution after a couple hours of frustration. Any advice appreciated!

1条回答
一纸荒年 Trace。
2楼-- · 2019-02-25 00:14

Thanks to the link from user ndm_yesterday, I generated the following solution:

public function findImages(Query $query, array $options) {
    $this->hasMany('ProductCategoriesProducts');

    $subquery = $this->ProductCategoriesProducts->find('all')->select([
        'Products.image'
    ])->join([
        [
            'table'     => 'products',
            'alias'     => 'Products',
            'type'      => 'LEFT',
            'conditions'=> [
                'ProductCategoriesProducts.product_id = Products.id'
            ]
        ]
    ])->where([
        'ProductCategoriesProducts.product_category_id = ProductCategories.id'
    ])->order([
        'Products.turnover' => 'DESC'
    ])->limit(1);

    $query->select([
        'ProductCategories.id',
        'ProductCategories.name',
        'ProductCategories__image' => $subquery
    ])->where([
        'ProductCategories.name <>' => 'Unsorted'
    ])->order([
        'ProductCategories.name'    => 'asc'
    ]);

    return $query;
}
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