Calculating the difference between two Java date i

2019-01-04 14:15发布

I'm using Java's java.util.Date class in Scala and want to compare a Date object and the current time. I know I can calculate the delta by using getTime():

(new java.util.Date()).getTime() - oldDate.getTime()

However, this just leaves me with a long representing milliseconds. Is there any simpler, nicer way to get a time delta?

30条回答
在下西门庆
2楼-- · 2019-01-04 14:52

A slightly simpler alternative:

System.currentTimeMillis() - oldDate.getTime()

As for "nicer": well, what exactly do you need? The problem with representing time durations as a number of hours and days etc. is that it may lead to inaccuracies and wrong expectations due to the complexity of dates (e.g. days can have 23 or 25 hours due to daylight savings time).

查看更多
混吃等死
3楼-- · 2019-01-04 14:53

You need to define your problem more clearly. You could just take the number of milliseconds between the two Date objects and divide by the number of milliseconds in 24 hours, for example... but:

  • This won't take time zones into consideration - Date is always in UTC
  • This won't take daylight saving time into consideration (where there can be days which are only 23 hours long, for example)
  • Even within UTC, how many days are there in August 16th 11pm to August 18th 2am? It's only 27 hours, so does that mean one day? Or should it be three days because it covers three dates?
查看更多
闹够了就滚
4楼-- · 2019-01-04 14:55

If you don't want to use JodaTime or similar, the best solution is probably this:

final static long MILLIS_PER_DAY = 24 * 3600 * 1000;
long msDiff= date1.getTime() - date2.getTime();
long daysDiff = Math.round(msDiff / ((double)MILLIS_PER_DAY));

The number of ms per day is not always the same (because of daylight saving time and leap seconds), but it's very close, and at least deviations due to daylight saving time cancel out over longer periods. Therefore dividing and then rounding will give a correct result (at least as long as the local calendar used does not contain weird time jumps other than DST and leap seconds).

Note that this still assumes that date1 and date2 are set to the same time of day. For different times of day, you'd first have to define what "date difference" means, as pointed out by Jon Skeet.

查看更多
Viruses.
5楼-- · 2019-01-04 14:56

Simple diff (without lib)

/**
 * Get a diff between two dates
 * @param date1 the oldest date
 * @param date2 the newest date
 * @param timeUnit the unit in which you want the diff
 * @return the diff value, in the provided unit
 */
public static long getDateDiff(Date date1, Date date2, TimeUnit timeUnit) {
    long diffInMillies = date2.getTime() - date1.getTime();
    return timeUnit.convert(diffInMillies,TimeUnit.MILLISECONDS);
}

And then can you call:

getDateDiff(date1,date2,TimeUnit.MINUTES);

to get the diff of the 2 dates in minutes unit.

TimeUnit is java.util.concurrent.TimeUnit, a standard Java enum going from nanos to days.


Human readable diff (without lib)

public static Map<TimeUnit,Long> computeDiff(Date date1, Date date2) {
    long diffInMillies = date2.getTime() - date1.getTime();
    List<TimeUnit> units = new ArrayList<TimeUnit>(EnumSet.allOf(TimeUnit.class));
    Collections.reverse(units);
    Map<TimeUnit,Long> result = new LinkedHashMap<TimeUnit,Long>();
    long milliesRest = diffInMillies;
    for ( TimeUnit unit : units ) {
        long diff = unit.convert(milliesRest,TimeUnit.MILLISECONDS);
        long diffInMilliesForUnit = unit.toMillis(diff);
        milliesRest = milliesRest - diffInMilliesForUnit;
        result.put(unit,diff);
    }
    return result;
}

http://ideone.com/5dXeu6

The output is something like Map:{DAYS=1, HOURS=3, MINUTES=46, SECONDS=40, MILLISECONDS=0, MICROSECONDS=0, NANOSECONDS=0}, with the units ordered.

You just have to convert that map to an user-friendly string.


Warning

The above code snippets compute a simple diff between 2 instants. It can cause problems during a daylight saving switch, like explained in this post. This means if you compute the diff between dates with no time you may have a missing day/hour.

In my opinion the date diff is kind of subjective, especially on days. You may:

  • count the number of 24h elapsed time: day+1 - day = 1 day = 24h

  • count the number of elapsed time, taking care of daylight savings: day+1 - day = 1 = 24h (but using midnight time and daylight savings it could be 0 day and 23h)

  • count the number of day switches, which means day+1 1pm - day 11am = 1 day, even if the elapsed time is just 2h (or 1h if there is a daylight saving :p)

My answer is valid if your definition of date diff on days match the 1st case

With JodaTime

If you are using JodaTime you can get the diff for 2 instants (millies backed ReadableInstant) dates with:

Interval interval = new Interval(oldInstant, new Instant());

But you can also get the diff for Local dates/times:

// returns 4 because of the leap year of 366 days
new Period(LocalDate.now(), LocalDate.now().plusDays(365*5), PeriodType.years()).getYears() 

// this time it returns 5
new Period(LocalDate.now(), LocalDate.now().plusDays(365*5+1), PeriodType.years()).getYears() 

// And you can also use these static methods
Years.yearsBetween(LocalDate.now(), LocalDate.now().plusDays(365*5)).getYears()
查看更多
Anthone
6楼-- · 2019-01-04 14:56

Since all the answers here are correct but use legacy java or 3rd party libs like joda or similar, I will just drop another way using new java.time classes in Java 8 and later. See Oracle Tutorial.

Use LocalDate and ChronoUnit:

LocalDate d1 = LocalDate.of(2017, 5, 1);
LocalDate d2 = LocalDate.of(2017, 5, 18);

long days = ChronoUnit.DAYS.between(d1, d2);
System.out.println( days );
查看更多
\"骚年 ilove
7楼-- · 2019-01-04 14:57

Using millisecond approach can cause problems in some locales.

Lets take, for example, the difference between the two dates 03/24/2007 and 03/25/2007 should be 1 day;

However, using the millisecond route, you'll get 0 days, if you run this in the UK!

/** Manual Method - YIELDS INCORRECT RESULTS - DO NOT USE**/  
/* This method is used to find the no of days between the given dates */  
public long calculateDays(Date dateEarly, Date dateLater) {  
   return (dateLater.getTime() - dateEarly.getTime()) / (24 * 60 * 60 * 1000);  
} 

Better way to implement this is to use java.util.Calendar

/** Using Calendar - THE CORRECT WAY**/  
public static long daysBetween(Calendar startDate, Calendar endDate) {  
  Calendar date = (Calendar) startDate.clone();  
  long daysBetween = 0;  
  while (date.before(endDate)) {  
    date.add(Calendar.DAY_OF_MONTH, 1);  
    daysBetween++;  
  }  
  return daysBetween;  
}  
查看更多
登录 后发表回答