I have this code
var Variable = "hello";
function say_hello ()
{
alert(Variable);
var Variable = "bye";
}
say_hello();
alert(Variable);
Now, when I first read this code, I thought it will alert "hello" two times, but the result I get is that it alerts "undefined" the first time, and "hello" second time. can someone explains to me why ?
What you are trying to do is alert a variable before initializing it. What you wanted was:
function say_hello() { var variable = "bye"; alert(variable); }
In JavaScript, all
var
declarations in a function are treated as if they appeared at the very top of the function body, no matter where they actually are in the code. Your function therefore was interpreted as if it were written like this:Note that it's just the declaration that's interpreted that way; the initialization expression happens where the
var
actually sits in your code. Thus, your function defined a local variable called "Variable", which hid the more global one. At the point thealert()
ran, the variable had not been initialized.This will give you the expected result. Like others said the
var
keyword will make 'scope local'. You'redefining
Variableafter you alert it
in say_hello so it isundefined
. Using the 'global scope' if you assign "bye" inside say_hello you won't get "hello" alerted twice.