How do I alter my existing table to create a range

2019-02-23 05:57发布

I have existing table which has 10 years of data (I have taken dump).

I would like to Range partition the existing table on one date key column within the table.

Most of the examples I see are with CREATE TABLE..PARTITION BY RANGE... to add new partitions. But my table is existing table.

I assume I need some ALTER statement.

ALTER TABLE TABLE_NAME
PARTITION BY RANGE(CREATED_DATE)
 PARTITION JAN16 VALUES LESS THAN (01-02-2016),
 PARTITION FEB16 VALUES LESS THAN (01-03-2016) AND GREATER THAN(31-01-2016),//OR?
 PARTITION MAR16 VALUES BETWEEN (01-03-2016) AND (31-03-2016),  //OR?

Two questions..

  1. Do I need Alter statement to add partitioning mechanism or need to work with create statement?

  2. What is the proper syntax for keeping each partition having only ONE MONTH data.

2条回答
Emotional °昔
2楼-- · 2019-02-23 06:51

Beacuse your table non-partitioned you have two options:

  1. Export data, drop table, create new patitioned table, import data.
  2. Use split then exchange partition method. https://oracle-base.com/articles/misc/partitioning-an-existing-table-using-exchange-partition

Also, if you want new partition per month read about SET INTERVAL. For example:

CREATE TABLE tst
   (col_date DATE)
 PARTITION BY RANGE (col_date) INTERVAL (NUMTOYMINTERVAL(1, 'MONTH'))
(PARTITION col_date_min VALUES LESS THAN (TO_DATE('2010-01-01', 'YYYY-MM-DD')));
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SAY GOODBYE
3楼-- · 2019-02-23 06:54

If you are using Oracle 12c Release 2 you could use single ALTER to convert non-partitioned table to partitioned one (this is one way trip):

CREATE TABLE my_tab ( a NUMBER(38,0), b NUMBER(38,0)); 

ALTER TABLE MY_TAB MODIFY PARTITION BY RANGE (a) INTERVAL (1000) (   
    PARTITION p1 VALUES LESS THAN (1000)) ONLINE;

You could convert indexes too, adding:

update indexes (index_name [local/global]);
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