I am using progress dialog.i need to stop the thread when user close the progressdialog .unfortunately it giving exception pls help me..
In inner class
class UpdateThread extends Thread{
public void run() {
while (true){
count=adapter.getCount();
try {
mHandler.post( new Runnable() {
public void run() {
Log.i(TAG,count+"count");
progressDialog.setMessage(count + "Device found");
}
});
Thread.sleep(300);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
Oncreate
updateThread=new UpdateThread();
progressDialog= new ProgressDialog(GroupListActivity.this);
synchronized (this) {
updateThread.start();
}
ondismissal
progressDialog.setOnDismissListener(new DialogInterface.OnDismissListener() {
@Override
public void onDismiss(DialogInterface dialog) {
try {
synchronized (this) {
updateThread.wait(300);
}
} catch (InterruptedException e) {
e.printStackTrace();
}
Log.i(TAG,"Thread is stopped");
}
});
It really looks like you're trying to use
synchronized
andwait
where you shouldn't be.If you really want to wait for the thread to finish, you should be doing something like this
In your
UpdateThread
:In your creation:
In your on dismiss:
Note, I added an exit condition to your thread so it will actually stop (as is, your thread will keep going). You'd probably want to make the exit condition private and add a setter for cleanliness. Also, I'm using
join
to properly wait for your thread to complete.You can only wait on an object if you already hold the lock on it, you could try:
... but I'm not really sure what you're trying to achieve with the locks.
This is wrong:
The problem is, what's going to wake this thread up? That is to say, how do you guarantee that the other thread won't call
foo.notify()
before the first thread callsfoo.wait()
? That's important because the foo object will not remember that it was notified if the notify call happens first. If there's only one notify(), and if it happens before the wait(), then the wait() will never return.Here's how wait and notify were meant to be used:
The most important things to to note in this example are that there is an explicit test for the condition (i.e., q.peek() != null), and that nobody changes the condition without locking the lock.
If the consumer is called first, then it will find the queue empty, and it will wait. There is no moment when the producer can slip in, add a Product to the queue, and then notify the lock until the consumer is ready to receive that notification.
On the other hand, if the producer is called first, then the consumer is guaranteed not to call wait().
The loop in the consumer is important for two reasons: One is that, if there is more than one consumer thread, then it is possible for one consumer to receive a notification, but then another consumer sneaks in and steals the Product from the queue. The only reasonable thing for the fist consumer to do in that case is wait again for the next Product. The other reason that the loop is important is that the Javadoc says Object.wait() is allowed to return even when the object has not been notified. That is called a "spurious wakeup", and the correct way to handle it is to go back and wait again.
Also note: The lock is
private
and the queue isprivate
. That guarantees that no other compilation unit is going to interfere with the synchronization in this compilation unit.And note: The lock is a different object from the queue itself. That guarantees that synchronization in this compilation unit will not interfere with whatever synchronization that the Queue implementation does (if any).
NOTE: My example re-invents a wheel to prove a point. In real code, you would use the put() and take() methods of an ArrayBlockingQueue which would take care of all of the waiting and notifying for you.