std::queue iteration

2019-01-04 11:35发布

I need to iterate over std::queue. www.cplusplus.com says:

By default, if no container class is specified for a particular queue class, the standard container class template deque is used.

So can I somehow get to the queue's underlying deque and iterate over it?

8条回答
Lonely孤独者°
2楼-- · 2019-01-04 12:13

Why not just make a copy of the queue that you want to iterate over, and remove items one at a time, printing them as you go? If you want to do more with the elements as you iterate, then a queue is the wrong data structure.

查看更多
劫难
3楼-- · 2019-01-04 12:19

If you need to iterate a queue ... queue isn't the container you need.
Why did you pick a queue?
Why don't you take a container that you can iterate over?


1.if you pick a queue then you say you want to wrap a container into a 'queue' interface: - front - back - push - pop - ...

if you also want to iterate, a queue has an incorrect interface. A queue is an adaptor that provides a restricted subset of the original container

2.The definition of a queue is a FIFO and by definition a FIFO is not iterable

查看更多
在下西门庆
4楼-- · 2019-01-04 12:21

If you need to iterate over a queue then you need something more than a queue. The point of the standard container adapters is to provide a minimal interface. If you need to do iteration as well, why not just use a deque (or list) instead?

查看更多
唯我独甜
5楼-- · 2019-01-04 12:22

I use something like this. Not very sophisticated but should work.

    queue<int> tem; 

    while(!q1.empty()) // q1 is your initial queue. 
    {
        int u = q1.front(); 

        // do what you need to do with this value.  

        q1.pop(); 
        tem.push(u); 
    }


    while(!tem.empty())
    {
        int u = tem.front(); 
        tem.pop(); 
        q1.push(u); // putting it back in our original queue. 
    }

It will work because when you pop something from q1, and push it into tem, it becomes the first element of tem. So, in the end tem becomes a replica of q1.

查看更多
相关推荐>>
6楼-- · 2019-01-04 12:24

you can save the original queue to a temporary queue. Then you simply do your normal pop on the temporary queue to go through the original one, for example:

queue tmp_q = original_q; //copy the original queue to the temporary queue

while (!tmp_q.empty())
{
    q_element = tmp_q.top();
    std::cout << q_element <<"\n";
    tmp_q.pop();
} 

At the end, the tmp_q will be empty but the original queue is untouched.

查看更多
三岁会撩人
7楼-- · 2019-01-04 12:28

While I agree with others that direct use of an iterable container is a preferred solution, I want to point out that the C++ standard guarantees enough support for a do-it-yourself solution in case you want it for whatever reason.

Namely, you can inherit from std::queue and use its protected member Container c; to access begin() and end() of the underlying container (provided that such methods exist there). Here is an example that works in VS 2010 and tested with ideone:

#include <queue>
#include <deque>
#include <iostream>

template<typename T, typename Container=std::deque<T> >
class iterable_queue : public std::queue<T,Container>
{
public:
    typedef typename Container::iterator iterator;
    typedef typename Container::const_iterator const_iterator;

    iterator begin() { return this->c.begin(); }
    iterator end() { return this->c.end(); }
    const_iterator begin() const { return this->c.begin(); }
    const_iterator end() const { return this->c.end(); }
};

int main() {
    iterable_queue<int> int_queue;
    for(int i=0; i<10; ++i)
        int_queue.push(i);
    for(auto it=int_queue.begin(); it!=int_queue.end();++it)
        std::cout << *it << "\n";
    return 0;
}
查看更多
登录 后发表回答