Convert JSON feed to NSDictionary

2019-01-04 11:08发布

Where JSON_CATEGORY_DATA_URL_STRING is my feed URL, which returns fine as:

[
    {
        "group":"For Sale",
        "code":"SSSS"
    },
    {
        "group":"For Sale",
        "category":"Wanted",
        "code":"SWNT"
    }
]

I cannot seem to get a nice NSDictionary (or NSArray) out of the following code:

+ (NSDictionary *)downloadJSON
{

NSDictionary *json_string;
NSString *dataURL = [NSString stringWithFormat:@"%@", JSON_CATEGORY_DATA_URL_STRING];
NSLog(@"%@",dataURL);
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:dataURL]];    
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

json_string = [[[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]autorelease];
NSDictionary *json_dict = (NSDictionary *)json_string;
NSLog(@"json_dict\n%@",json_dict);
    NSLog(@"json_string\n%@",json_string);

return json_string;
}

I've read many posts on this, but am not getting it.

5条回答
Bombasti
2楼-- · 2019-01-04 11:26

You need to use JSON parser. here is the edited code

+ (NSDictionary *)downloadJSON
{

NSDictionary *json_string;
NSString *dataURL = [NSString stringWithFormat:@"%@", JSON_CATEGORY_DATA_URL_STRING];
NSLog(@"%@",dataURL);
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:dataURL]];    
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

json_string = [[[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]autorelease];
//JSONValue is a function that will return the appropriate object like dictionary or array depending on your json string.
NSDictionary *json_dict = [json_string JSONValue];
NSLog(@"json_dict\n%@",json_dict);
    NSLog(@"json_string\n%@",json_string);

return json_dict;
}

this should be the code to get the NSDictionary. but you json string is an array so instead use .

+ (NSArray *)downloadJSON
{

NSDictionary *json_string;
NSString *dataURL = [NSString stringWithFormat:@"%@", JSON_CATEGORY_DATA_URL_STRING];
NSLog(@"%@",dataURL);
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:dataURL]];    
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

json_string = [[[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]autorelease];
NSArray *json_dict = [json_string JSONValue];
NSLog(@"json_dict\n%@",json_dict);
    NSLog(@"json_string\n%@",json_string);

return json_dict;
}

Edit: you need to use JSON.framework to call JSONValue method.
also you need to return json_dict instead of json_string as json_string is of NSString type and not NSDictionary or NSArray.
and dont autorelease it, as it is your class variable

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贼婆χ
3楼-- · 2019-01-04 11:31

You can't just cast a string as a dictionary and expect it to parse the JSON. You must use a JSON parsing library to take that string and convert it into a dictionary.

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老娘就宠你
4楼-- · 2019-01-04 11:41

create method to fetchjson data.Pass your url in urlwithstring.

-(void)fetchjsondata
{
     NSString *login= [[NSString stringWithFormat:@"your url string"]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    NSLog(@"----%@", login);
    NSURL *url = [NSURL URLWithString:[login stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
    //-- Get request and response though URL
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc]initWithURL:url];


    [NSURLConnection sendAsynchronousRequest:request
                                       queue:[NSOperationQueue mainQueue]
                           completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
                               dispatch_async(dispatch_get_main_queue(), ^{
                                   if (data) {
                                       dic_property= [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:nil];
                                       NSLog(@"%@", dic_property);
                                       NSLog(@"counts=%d",[[dic_property objectForKey:@"Data"]count]);



                                   }
                                   else {
                                       NSLog(@"network error, %@", [error localizedFailureReason]);
                                   }
                               });

                           }];

}

call fetchjsonmethod in anywhere.

[NSThread detachNewThreadSelector:@selector(fetchdata) toTarget:self withObject:nil];

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不美不萌又怎样
5楼-- · 2019-01-04 11:43

With IOS5 you can use NSJSONSerialization for serializing the JSON.

NSDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];

Hope this help you.

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对你真心纯属浪费
6楼-- · 2019-01-04 11:43

I made a class that makes this task easier. It uses iOS 5's NSJSONSerialization. Clone it from github here.

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