What's the fastest way to convert an interleav

2019-02-21 20:00发布

I have a stream of incoming data that has interleaved real and imaginary integers. Converting these to complex64 values is the slowest operation in my program. This is my current approach:

import numpy as np

a = np.zeros(1000000, dtype=np.int16)
b = np.complex64(a[::2]) + np.complex64(1j) * np.complex64(a[1::2])

Can I do better without making a C extension or using something like cython? If I can't do better, what's my easiest approach using a technology like one of these?

1条回答
做个烂人
2楼-- · 2019-02-21 20:49
[~]
|1> import numpy as np

[~]
|2> a = np.zeros(1000000, dtype=np.int16)

[~]
|3> b = a.astype(np.float32).view(np.complex64)

[~]
|4> b.shape
(500000,)

[~]
|5> b.dtype
dtype('complex64')
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