Filter directory when using shutil.copytree?

2019-02-21 15:13发布

Is there a way I can filter a directory by using the absolute path to it?

shutil.copytree(directory,
                target_dir,
                ignore = shutil.ignore_patterns("/Full/Path/To/aDir/Common")) 

This doesn't seem to work when trying to filter the "Common" Directory located under "aDir". If I do this:

shutil.copytree(directory,
                target_dir,
                ignore = shutil.ignore_patterns("Common"))

It works, but every directory called Common will be filtered in that "tree", which is not what I want.

Any suggestions ?

Thanks.

3条回答
仙女界的扛把子
2楼-- · 2019-02-21 15:50

The API for shutil.ignore_patterns() doesn't support absolute paths, but it is trivially easy to roll your own variant.

As a starting point, look at the source code for *ignore_patterns*:

def ignore_patterns(*patterns):
    """Function that can be used as copytree() ignore parameter.

    Patterns is a sequence of glob-style patterns
    that are used to exclude files"""
    def _ignore_patterns(path, names):
        ignored_names = []
        for pattern in patterns:
            ignored_names.extend(fnmatch.filter(names, pattern))
        return set(ignored_names)
    return _ignore_patterns

You can see that it returns a function that accepts a path and list of names, and it returns a set of names to ignore. To support your use case, create you own similar function that uses takes advantage of path argument. Pass your function to the ignore parameter in the call to copytree().

Alternatively, don't use shutil as-is. The source code is short and sweet, so it isn't hard to cut, paste, and customize.

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劫难
3楼-- · 2019-02-21 15:58

You'll want to make your own ignore function, which checks the current directory being processed and returns a list containing 'Common' only if the dir is '/Full/Path/To/aDir'.

def ignore_full_path_common(dir, files):
    if dir == '/Full/Path/To/aDir':
        return ['Common']
    return []

shutil.copytree(directory, target_dir, ignore=ignore_full_path_common)
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老娘就宠你
4楼-- · 2019-02-21 16:05

You can make your own ignore function:

shutil.copytree('/Full/Path', 'target',
              ignore=lambda directory, contents: ['Common'] if directory == '/Full/Path/To/aDir' else [])

Or, if you want to be able to call copytree with a relative path:

import os.path
def ignorePath(path):
  def ignoref(directory, contents):
    return (f for f in contents if os.abspath(os.path.join(directory, f)) == path)
  return ignoref

shutil.copytree('Path', 'target', ignore=ignorePath('/Full/Path/To/aDir/Common'))

From the docs:

If ignore is given, it must be a callable that will receive as its arguments the directory being visited by copytree(), and a list of its contents, as returned by os.listdir(). Since copytree() is called recursively, the ignore callable will be called once for each directory that is copied. The callable must return a sequence of directory and file names relative to the current directory (i.e. a subset of the items in its second argument); these names will then be ignored in the copy process. ignore_patterns() can be used to create such a callable that ignores names based on glob-style patterns.

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