This question already has an answer here:
Let's say I have something as follows:
for(var i = 0; i < length; i++){
var variable = variables[i];
otherVariable.doSomething(variable, function(err){ //callback for when doSomething ends
do something else with variable;
}
By the time the callbacks are called, variable
will inevitably be the last variable for all the callbacks, instead of being a different one for each callback, as I would like. I realize that I could pass variable
to doSomething()
and then get that passed back as part of the callback, but doSomething()
is part of an external library, and I'd rather not mess around with the source code for that.
Do those of you that know JavaScript better than I do know if there are any alternative ways to do what I'd like to do?
Best, and thanks,
Sami
Ok I've seemed to figure this out. What I needed to do was to put a
function(var)
wrapper aroundotherVariable.doSomething()
, so the updated code looks as follows:hope this helps anybody else that gets stuck on something like this in the future!
@aparker42, i'd still love to hear your answer to my question in the comment to your question, since that still does confuse me.
EDIT: of course, since this is javascript, you wouldn't want to use
var
as a variable name.A common, if ugly, way of dealing with this situation is to use another function that is immediately invoked to create a scope to hold the variable.
Notice that inside the immediately invoked function the callback that is being created, and returned, references the parameter to the function
v
and not the outsidevariable
. To make this read much better I would suggest extracting the constructor of the callback as a named function.