Updating Twitter background via API

Question

I'm having a little trouble updating backgrounds via Twitter's API.

$target_url = "http://www.google.com/logos/11th_birthday.gif";
$ch = curl_init();
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Expect:'));
curl_setopt($ch, CURLOPT_USERAGENT, $userAgent);
curl_setopt($ch, CURLOPT_URL,$target_url);
curl_setopt($ch, CURLOPT_FAILONERROR, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_AUTOREFERER, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
$html = curl_exec($ch);

$content = $to->OAuthRequest('http://twitter.com/account/update_profile_background_image.xml', array('profile_background_image_url' => $html), 'POST');

When I try to pull the raw data via cURL or file_get_contents, I get this...

Expectation Failed The expectation given in the Expect request-header field could not be met by this server. The client sent Expect: 100-continue but we only allow the 100-continue expectation.

Answer 1

OK, you can't direct Twitter to a URL, it won't accept that. Looking around a bit I've found that the best way is to download the image to the local server and then pass that over to Twitter almost like a form upload.

Try the following code, and let me know what you get.

// The URL from an external (or internal) server we want to grab
$url = 'http://www.google.com/logos/11th_birthday.gif';

// We need to grab the file name of this, unless you want to create your own
$filename = basename($url);

// This is where we'll be saving our new file to. Replace LOCALPATH with the path you would like to save the file to, i.e. www/home/content/my_directory/
$newfilename = 'LOCALPATH' . $filename;

// Copy it over, PHP will handle the overheads.
copy($url, $newfilename);

// Now it's OAuth time... fingers crossed!
$content = $to->OAuthRequest('http://twitter.com/account/update_profile_background_image.xml', array('profile_background_image_url' => $newfilename), 'POST');

// Echo something so you know it went through
print "done";

Answer 2

Well, given the error message, it sounds like you should load the URL's contents yourself, and post the data directly. Have you tried that?