POST request with a simple string in body with Ala

2019-01-04 08:26发布

how is it possible to send a POST request with a simple string in the HTTP body with Alamofire in my iOS app?

As default Alamofire needs parameters for a request:

Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: ["foo": "bar"])

These parameters contain key-value-pairs. But I don't want to send a request with a key-value string in the HTTP body.

I mean something like this:

Alamofire.request(.POST, "http://mywebsite.com/post-request", body: "myBodyString")

9条回答
我只想做你的唯一
2楼-- · 2019-01-04 08:52

Your example Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: ["foo": "bar"]) already contains "foo=bar" string as its body. But if you really want string with custom format. You can do this:

Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: [:], encoding: .Custom({
            (convertible, params) in
            var mutableRequest = convertible.URLRequest.copy() as NSMutableURLRequest
            mutableRequest.HTTPBody = "myBodyString".dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
            return (mutableRequest, nil)
        }))

Note: parameters should not be nil

UPDATE (Alamofire 4.0, Swift 3.0):

In Alamofire 4.0 API has changed. So for custom encoding we need value/object which conforms to ParameterEncoding protocol.

extension String: ParameterEncoding {

    public func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        var request = try urlRequest.asURLRequest()
        request.httpBody = data(using: .utf8, allowLossyConversion: false)
        return request
    }

}

Alamofire.request("http://mywebsite.com/post-request", method: .post, parameters: [:], encoding: "myBody", headers: [:])
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唯我独甜
3楼-- · 2019-01-04 08:54

If you use Alamofire, it is enough to encoding type to "URLEncoding.httpBody"

With that, you can send your data as a string in the httpbody allthough you defined it json in your code.

It worked for me..

UPDATED for

  var url = "http://..."
    let _headers : HTTPHeaders = ["Content-Type":"application/x-www-form-urlencoded"]
    let params : Parameters = ["grant_type":"password","username":"mail","password":"pass"]

    let url =  NSURL(string:"url" as String)

    request(url, method: .post, parameters: params, encoding: URLEncoding.httpBody , headers: _headers).responseJSON(completionHandler: {
        response in response

        let jsonResponse = response.result.value as! NSDictionary

        if jsonResponse["access_token"] != nil
        {
            access_token = String(describing: jsonResponse["accesstoken"]!)

        }

    })
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forever°为你锁心
4楼-- · 2019-01-04 09:00

Xcode 8.X , Swift 3.X

Easy Use;

 let params:NSMutableDictionary? = ["foo": "bar"];
            let ulr =  NSURL(string:"http://mywebsite.com/post-request" as String)
            let request = NSMutableURLRequest(url: ulr! as URL)
            request.httpMethod = "POST"
            request.setValue("application/json", forHTTPHeaderField: "Content-Type")
            let data = try! JSONSerialization.data(withJSONObject: params!, options: JSONSerialization.WritingOptions.prettyPrinted)

            let json = NSString(data: data, encoding: String.Encoding.utf8.rawValue)
            if let json = json {
                print(json)
            }
            request.httpBody = json!.data(using: String.Encoding.utf8.rawValue);


            Alamofire.request(request as! URLRequestConvertible)
                .responseJSON { response in
                    // do whatever you want here
                   print(response.request)  
                   print(response.response) 
                   print(response.data) 
                   print(response.result)

            }
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5楼-- · 2019-01-04 09:04

I've used answer of @afrodev as reference. In my case I take parameter to my function as string that have to be posted in request. So, here is the code:

func defineOriginalLanguage(ofText: String) {
    let text =  ofText
    let stringURL = basicURL + "identify?version=2018-05-01"
    let url = URL(string: stringURL)

    var request = URLRequest(url: url!)
    request.httpMethod = HTTPMethod.post.rawValue
    request.setValue("text/plain", forHTTPHeaderField: "Content-Type")
    request.httpBody = text.data(using: .utf8)

    Alamofire.request(request)
        .responseJSON { response in
            print(response)
    }
}
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\"骚年 ilove
6楼-- · 2019-01-04 09:05

You can do this:

  1. I created a separated request Alamofire object.
  2. Convert string to Data
  3. Put in httpBody the data

    var request = URLRequest(url: URL(string: url)!)
    request.httpMethod = HTTPMethod.post.rawValue
    request.setValue("application/json", forHTTPHeaderField: "Content-Type")
    
    let pjson = attendences.toJSONString(prettyPrint: false)
    let data = (pjson?.data(using: .utf8))! as Data
    
    request.httpBody = data
    
    Alamofire.request(request).responseJSON { (response) in
    
    
        print(response)
    
    }
    
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Melony?
7楼-- · 2019-01-04 09:08
func paramsFromJSON(json: String) -> [String : AnyObject]?
{
    let objectData: NSData = (json.dataUsingEncoding(NSUTF8StringEncoding))!
    var jsonDict: [ String : AnyObject]!
    do {
        jsonDict = try NSJSONSerialization.JSONObjectWithData(objectData, options: .MutableContainers) as! [ String : AnyObject]
        return jsonDict
    } catch {
        print("JSON serialization failed:  \(error)")
        return nil
    }
}

let json = Mapper().toJSONString(loginJSON, prettyPrint: false)

Alamofire.request(.POST, url + "/login", parameters: paramsFromJSON(json!), encoding: .JSON)
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