RSA encrypt/decrypt between C and python

2019-02-20 06:35发布

I have server written in python and client in C . Their job is to send a secret message from server to client which is encrypted with RSA private key. I am using openssl/rsa.h library, that is I initialize a rsa object with a private key and encrypte a message with RSA_public_encrypt(length_of_message, "Secret Message", to, rsa, RSA_PKCS1_PADDING) . Then I send this encrypted message to python server and try to decrypt it with same private key using from Crypto.PublicKey import RSA library. Problem is that it does not decrypt it properly. It always outputs 128-bit length message where the secret message is randomly placed in it (e.g. '\x23\xa3x\43...Secret Message\xef\x4a'), where it should normally return just Secret Message.

2条回答
祖国的老花朵
2楼-- · 2019-02-20 06:47

Is it possible to create a same pair of RSA key in Python and C . please find the code below and let me know if any modification needed to get it worked.

Code in python

   key = RSA.generate(2048)
   file_out_pub = open("pubkey.der", "wb")
   file_out_pub.write(key.publickey().exportKey())
   file_out_pub.close()
   file_out_pub = open("pubkey.der", "`enter code here`r")
   public_key = RSA.importKey(file_out_pub.read())
   cipher = PKCS1_OAEP.new(public_key)
   password = pw
   ciphertext = cipher.encrypt(password)

Code in C

 int clen = 0, num, ret;
 clen = strnlen_s(req->pw,2048);
 unsigned char ptext[2048];
 RSA *rsa = RSA_new();
 BIGNUM *e = BN_new();
 ret = RSA_generate_key_ex(rsa, 2048, e, NULL );
 num = RSA_private_decrypt(clen, req->pw , ptext, rsa, RSA_PKCS1_OAEP_PADDING);
 // Start authentication process
 strncpy(req->pw,ptext,MAX_PASSWORD_STR);
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贼婆χ
3楼-- · 2019-02-20 06:51

The problem was about the padding. Python's rsa module decrypts result with PKCS1 padding and does not removes padding. With the function below which I have taken from here problem was solved:

def pkcs1_unpad(text):
if len(text) > 0 and text[0] == '\x02':
    # Find end of padding marked by nul
    pos = text.find('\x00')
    if pos > 0:
        return text[pos+1:]
return None
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