What does the 'static' keyword do in a cla

2018-12-30 23:35发布

To be specific, I was trying this code:

package hello;

public class Hello {

    Clock clock = new Clock();

    public static void main(String args[]) {
        clock.sayTime();
    }
}

But it gave the error

Cannot access non-static field in static method main

So I changed the declaration of clock to this:

static Clock clock = new Clock();

And it worked. What does it mean to put that keyword before the declaration? What exactly will it do and/or restrict in terms of what can be done to that object?

21条回答
余生无你
2楼-- · 2018-12-31 00:17

Basic usage of static members...

public class Hello
{
    // value / method
    public static String staticValue;
    public String nonStaticValue;
}

class A
{
    Hello hello = new Hello();
    hello.staticValue = "abc";
    hello.nonStaticValue = "xyz";
}

class B
{
    Hello hello2 = new Hello(); // here staticValue = "abc"
    hello2.staticValue; // will have value of "abc"
    hello2.nonStaticValue; // will have value of null
}

That's how you can have values shared in all class members without sending class instance Hello to other class. And whit static you don't need to create class instance.

Hello hello = new Hello();
hello.staticValue = "abc";

You can just call static values or methods by class name:

Hello.staticValue = "abc";
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浪荡孟婆
3楼-- · 2018-12-31 00:18

The static keyword means that something (a field, method or nested class) is related to the type rather than any particular instance of the type. So for example, one calls Math.sin(...) without any instance of the Math class, and indeed you can't create an instance of the Math class.

For more information, see the relevant bit of Oracle's Java Tutorial.


Sidenote

Java unfortunately allows you to access static members as if they were instance members, e.g.

// Bad code!
Thread.currentThread().sleep(5000);
someOtherThread.sleep(5000);

That makes it look as if sleep is an instance method, but it's actually a static method - it always makes the current thread sleep. It's better practice to make this clear in the calling code:

// Clearer
Thread.sleep(5000);
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姐姐魅力值爆表
4楼-- · 2018-12-31 00:19

static members belong to the class instead of a specific instance.

It means that only one instance of a static field exists[1] even if you create a million instances of the class or you don't create any. It will be shared by all instances.

Since static methods also do not belong to a specific instance, they can't refer to instance members. In the example given, main does not know which instance of the Hello class (and therefore which instance of the Clock class) it should refer to. static members can only refer to static members. Instance members can, of course access static members.

Side note: Of course, static members can access instance members through an object reference.

Example:

public class Example {
    private static boolean staticField;
    private boolean instanceField;
    public static void main(String[] args) {
        // a static method can access static fields
        staticField = true;

        // a static method can access instance fields through an object reference
        Example instance = new Example();
        instance.instanceField = true;
    }

[1]: Depending on the runtime characteristics, it can be one per ClassLoader or AppDomain or thread, but that is beside the point.

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永恒的永恒
5楼-- · 2018-12-31 00:20

This discussion has so far ignored classloader considerations. Strictly speaking, Java static fields are shared between all instances of a class for a given classloader.

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情到深处是孤独
6楼-- · 2018-12-31 00:21

It means that there is only one instance of "clock" in Hello, not one per each separate instance of the "Hello" class, or more-so, it means that there will be one commonly shared "clock" reference among all instances of the "Hello" class.

So if you were to do a "new Hello" anywhere in your code: A- in the first scenario (before the change, without using "static"), it would make a new clock every time a "new Hello" is called, but B- in the second scenario (after the change, using "static"), every "new Hello" instance would still share and use the initial and same "clock" reference first created.

Unless you needed "clock" somewhere outside of main, this would work just as well:

package hello;
public class Hello
{
    public static void main(String args[])
    {
      Clock clock=new Clock();
      clock.sayTime();    
    }
}
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大哥的爱人
7楼-- · 2018-12-31 00:21

Static means that you don't have to create an instance of the class to use the methods or variables associated with the class. In your example, you could call:

Hello.main(new String[]()) //main(...) is declared as a static function in the Hello class

directly, instead of:

Hello h = new Hello();
h.main(new String[]()); //main(...) is a non-static function linked with the "h" variable

From inside a static method (which belongs to a class) you cannot access any members which are not static, since their values depend on your instantiation of the class. A non-static Clock object, which is an instance member, would have a different value/reference for each instance of your Hello class, and therefore you could not access it from the static portion of the class.

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