How to determine the screen width in terms of dp o

2019-01-04 04:50发布

I need to code the layout of the android widgets using dip/dp (in java files). At runtime if I code,

int pixel=this.getWindowManager().getDefaultDisplay().getWidth();

this return the screen width in pixels (px). To convert this to dp, I coded:

int dp =pixel/(int)getResources().getDisplayMetrics().density ;

This does not seem to be returning correct answer. I made the emulator of WVGA800 whose screen resolution is 480 by 800. When the run the emulator and let the code print the values of pixel and dp, it came to 320 in both. This emulator is 240 dpi whose scale factor would be 0.75.

标签: android dip
6条回答
Deceive 欺骗
2楼-- · 2019-01-04 05:29

How about using this instead ?

final DisplayMetrics displayMetrics=getResources().getDisplayMetrics();
final float screenWidthInDp=displayMetrics.widthPixels/displayMetrics.density;
final float screenHeightInDp=displayMetrics.heightPixels/displayMetrics.density;
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Lonely孤独者°
3楼-- · 2019-01-04 05:29

Your problem is with casting the float to an int, losing precision. You should also multiply with the factor and not divide.

Do this:

int dp = (int)(pixel*getResources().getDisplayMetrics().density);
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smile是对你的礼貌
4楼-- · 2019-01-04 05:31

I stumbled upon this question from Google, and later on I found an easy solution valid for API >= 13.

For future references:

Configuration configuration = yourActivity.getResources().getConfiguration();
int screenWidthDp = configuration.screenWidthDp; //The current width of the available screen space, in dp units, corresponding to screen width resource qualifier.
int smallestScreenWidthDp = configuration.smallestScreenWidthDp; //The smallest screen size an application will see in normal operation, corresponding to smallest screen width resource qualifier.

See Configuration class reference

Edit: As noted by Nick Baicoianu, this returns the usable width/height of the screen (which should be the interesting ones in most uses). If you need the actual display dimensions stick to the top answer.

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Viruses.
5楼-- · 2019-01-04 05:38
DisplayMetrics displayMetrics = new DisplayMetrics();

getWindowManager().getDefaultDisplay().getMetrics(displayMetrics);

int width_px = Resources.getSystem().getDisplayMetrics().widthPixels;

int height_px =Resources.getSystem().getDisplayMetrics().heightPixels;

int pixeldpi = Resources.getSystem().getDisplayMetrics().densityDpi;


int width_dp = (width_px/pixeldpi)*160;
int height_dp = (height_px/pixeldpi)*160;
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迷人小祖宗
6楼-- · 2019-01-04 05:46

Try this

Display display = getWindowManager().getDefaultDisplay();
DisplayMetrics outMetrics = new DisplayMetrics ();
display.getMetrics(outMetrics);

float density  = getResources().getDisplayMetrics().density;
float dpHeight = outMetrics.heightPixels / density;
float dpWidth  = outMetrics.widthPixels / density;

OR

Thanks @Tomáš Hubálek

DisplayMetrics displayMetrics = context.getResources().getDisplayMetrics();    
float dpHeight = displayMetrics.heightPixels / displayMetrics.density;
float dpWidth = displayMetrics.widthPixels / displayMetrics.density;
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够拽才男人
7楼-- · 2019-01-04 05:47

You are missing default density value of 160.

    2 px = 3 dip if dpi == 80(ldpi), 320x240 screen
    1 px = 1 dip if dpi == 160(mdpi), 480x320 screen
    3 px = 2 dip if dpi == 240(hdpi), 840x480 screen

In other words, if you design you layout with width equal to 160dip in portrait mode, it will be half of the screen on all ldpi/mdpi/hdpi devices(except tablets, I think)

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