How to force os.system() to use bash inste

Question

I've tried what's told in How to force /bin/bash interpreter for oneliners

By doing

os.system('GREPDB="my command"')
os.system('/bin/bash -c \'$GREPDB\'')

However no luck, unfortunately I need to run this command with bash and subp isn't an option in this environment, I'm limited to python 2.4. Any suggestions to get me in the right direction?

Answer 1

Both commands are executed in different subshells.

Setting variables in the first system call does not affect the second system call.

You need to put two command in one string (combining them with ;).

>>> import os
>>> os.system('GREPDB="echo 123"; /bin/bash -c "$GREPDB"')
123
0

NOTE You need to use "$GREPDB" instead of '$GREPDBS'. Otherwise it is interpreted literally instead of being expanded.

If you can use subprocess:

>>> import subprocess
>>> subprocess.call('/bin/bash -c "$GREPDB"', shell=True,
...                 env={'GREPDB': 'echo 123'})
123
0

Answer 2

I use this:

subprocess.call(["bash","-c",cmd])

//OK, ignore this because I have not notice subprocess not considered.

Answer 3

I searched this command for some days and found really working code:

import subprocess

def bash_command(cmd):
    subprocess.Popen(['/bin/bash', '-c', cmd])

code="abcde"
// you can use echo options such as -e
bash_command('echo -ne "'+code+'"')

Output:

abcde

Answer 4

subprocess.Popen(cmd, shell=True, executable='/bin/bash')

Answer 5

The solution below still initially invokes a shell, but it switches to bash for the command you are trying to execute:

os.system('/bin/bash -c "echo hello world"')

Answer 6

Is it possible, for you, to change the default shell of the user who starts the application ? You could try to use chsh to do it.