How to open the Google Play Store directly from my

Question

I have open the google play store using the follwing code

Intent i = new Intent(android.content.Intent.ACTION_VIEW);
i.setData(Uri.parse("https://play.google.com/store/apps/details?id=my packagename "));
startActivity(i);.

But it shows me a Complete Action View as to select the option (browser/play store). I need to open the application in playstore directly.

Answer 1

You can do this using the market:// prefix.

final String appPackageName = getPackageName(); // getPackageName() from Context or Activity object
try {
    startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName)));
} catch (android.content.ActivityNotFoundException anfe) {
    startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}

We use a try/catch block here because an Exception will be thrown if the Play Store is not installed on the target device.

NOTE: any app can register as capable of handling the market://details?id=<appId> Uri, if you want to specifically target Google Play check the Berťák answer

Answer 2

Very late in the party Official docs are here. And code described is

Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(
    "https://play.google.com/store/apps/details?id=com.example.android"));
intent.setPackage("com.android.vending");
startActivity(intent);

As you configure this intent, pass "com.android.vending" into Intent.setPackage() so that users see your app's details in the Google Play Store app instead of a chooser. for KOTLIN

val intent = Intent(Intent.ACTION_VIEW).apply {
    data = Uri.parse(
            "https://play.google.com/store/apps/details?id=com.example.android")
    setPackage("com.android.vending")
}
startActivity(intent)

If you have published an instant app using Google Play Instant, you can launch the app as follows:

Intent intent = new Intent(Intent.ACTION_VIEW);
Uri.Builder uriBuilder = Uri.parse("https://play.google.com/store/apps/details")
    .buildUpon()
    .appendQueryParameter("id", "com.example.android")
    .appendQueryParameter("launch", "true");

// Optional parameters, such as referrer, are passed onto the launched
// instant app. You can retrieve these parameters using
// Activity.getIntent().getData().
uriBuilder.appendQueryParameter("referrer", "exampleCampaignId");

intent.setData(uriBuilder.build());
intent.setPackage("com.android.vending");
startActivity(intent);

For KOTLIN

val uriBuilder = Uri.parse("https://play.google.com/store/apps/details")
        .buildUpon()
        .appendQueryParameter("id", "com.example.android")
        .appendQueryParameter("launch", "true")

// Optional parameters, such as referrer, are passed onto the launched
// instant app. You can retrieve these parameters using Activity.intent.data.
uriBuilder.appendQueryParameter("referrer", "exampleCampaignId")

val intent = Intent(Intent.ACTION_VIEW).apply {
    data = uriBuilder.build()
    setPackage("com.android.vending")
}
startActivity(intent)

Answer 3

While Eric's answer is correct and Berťák's code also works. I think this combines both more elegantly.

try {
    Intent appStoreIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName));
    appStoreIntent.setPackage("com.android.vending");

    startActivity(appStoreIntent);
} catch (android.content.ActivityNotFoundException exception) {
    startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
}

By using setPackage, you force the device to use the Play Store. If there is no Play Store installed, the Exception will be caught.

Answer 4

All of the above answers open Google Play in a new view of the same app, if you actually want to open Google Play (or any other app) independently:

Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.android.vending");

// package name and activity
ComponentName comp = new ComponentName("com.android.vending",
                                       "com.google.android.finsky.activities.LaunchUrlHandlerActivity"); 
launchIntent.setComponent(comp);

// sample to open facebook app
launchIntent.setData(Uri.parse("market://details?id=com.facebook.katana"));
startActivity(launchIntent);

The important part is that actually opens google play or any other app independently.

Most of what I have seen uses the approach of the other answers and it was not what I needed hopefully this helps somebody.

Regards.

Answer 5

Many answers here suggest to use Uri.parse("market://details?id=" + appPackageName)) to open Google Play, but I think it is insufficient in fact:

Some third-party applications can use its own intent-filters with "market://" scheme defined, thus they can process supplied Uri instead of Google Play (I experienced this situation with e.g.SnapPea application). The question is "How to open the Google Play Store?", so I assume, that you do not want to open any other application. Please also note, that e.g. app rating is only relevant in GP Store app etc...

To open Google Play AND ONLY Google Play I use this method:

public static void openAppRating(Context context) {
    // you can also use BuildConfig.APPLICATION_ID
    String appId = context.getPackageName();
    Intent rateIntent = new Intent(Intent.ACTION_VIEW,
        Uri.parse("market://details?id=" + appId));
    boolean marketFound = false;

    // find all applications able to handle our rateIntent
    final List<ResolveInfo> otherApps = context.getPackageManager()
        .queryIntentActivities(rateIntent, 0);
    for (ResolveInfo otherApp: otherApps) {
        // look for Google Play application
        if (otherApp.activityInfo.applicationInfo.packageName
                .equals("com.android.vending")) {

            ActivityInfo otherAppActivity = otherApp.activityInfo;
            ComponentName componentName = new ComponentName(
                    otherAppActivity.applicationInfo.packageName,
                    otherAppActivity.name
                    );
            // make sure it does NOT open in the stack of your activity
            rateIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            // task reparenting if needed
            rateIntent.addFlags(Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
            // if the Google Play was already open in a search result
            //  this make sure it still go to the app page you requested
            rateIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            // this make sure only the Google Play app is allowed to
            // intercept the intent
            rateIntent.setComponent(componentName);
            context.startActivity(rateIntent);
            marketFound = true;
            break;

        }
    }

    // if GP not present on device, open web browser
    if (!marketFound) {
        Intent webIntent = new Intent(Intent.ACTION_VIEW,
            Uri.parse("https://play.google.com/store/apps/details?id="+appId));
        context.startActivity(webIntent);
    }
}

The point is that when more applications beside Google Play can open our intent, app-chooser dialog is skipped and GP app is started directly.

UPDATE: Sometimes it seems that it opens GP app only, without opening the app's profile. As TrevorWiley suggested in his comment, Intent.FLAG_ACTIVITY_CLEAR_TOP could fix the problem. (I didn't test it myself yet...)

See this answer for understanding what Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED does.

Answer 6

If you want to open Google Play store from your app then use this command directy: market://details?gotohome=com.yourAppName, it will open your app's Google Play store pages.

• Web: http://play.google.com/store/apps/details?id=
• App: market://details?id=

Show all apps by a specific publisher

• Web: http://play.google.com/store/search?q=pub:
• App: market://search?q=pub:

Search for apps that using the Query on its title or description

• Web: http://play.google.com/store/search?q=
• App: market://search?q=

Reference: https://tricklio.com/market-details-gotohome-1/