Default value of a type at Runtime [duplicate]

Question

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• how to get the default value of a type if the type is only known as System.Type? [duplicate] 3 answers

For any given type i want to know its default value.

In C#, there is a keyword called default for doing this like

object obj = default(Decimal);

but I have an instance of Type (called myType) and if I say this,

object obj = default(myType);

it doesn't work

Is there any good way of doing this? I know that a huge switch block will work but thats not a good choice.

Answer 1

Here's a function that will return the default value for a nullable type (in other words, it returns 0 for both Decimal and Decimal?):

public static object DefaultValue(Type maybeNullable)
{
    Type underlying = Nullable.GetUnderlyingType(maybeNullable);
    if (underlying != null)
        return Activator.CreateInstance(underlying);
    return Activator.CreateInstance(maybeNullable);
}

Answer 2

Having solved this problem in my own systems, here is a method for correctly determining the default value of an arbitrary Type at run time, which has been tested against thousands of Types:

    /// <summary>
    /// [ <c>public static object GetDefault(this Type type)</c> ]
    /// <para></para>
    /// Retrieves the default value for a given Type
    /// </summary>
    /// <param name="type">The Type for which to get the default value</param>
    /// <returns>The default value for <paramref name="type"/></returns>
    /// <remarks>
    /// If a null Type, a reference Type, or a System.Void Type is supplied, this method always returns null.  If a value type 
    /// is supplied which is not publicly visible or which contains generic parameters, this method will fail with an 
    /// exception.
    /// </remarks>
    /// <example>
    /// To use this method in its native, non-extension form, make a call like:
    /// <code>
    ///     object Default = DefaultValue.GetDefault(someType);
    /// </code>
    /// To use this method in its Type-extension form, make a call like:
    /// <code>
    ///     object Default = someType.GetDefault();
    /// </code>
    /// </example>
    /// <seealso cref="GetDefault&lt;T&gt;"/>
    public static object GetDefault(this Type type)
    {
        // If no Type was supplied, if the Type was a reference type, or if the Type was a System.Void, return null
        if (type == null || !type.IsValueType || type == typeof(void))
            return null;

        // If the supplied Type has generic parameters, its default value cannot be determined
        if (type.ContainsGenericParameters)
            throw new ArgumentException(
                "{" + MethodInfo.GetCurrentMethod() + "} Error:\n\nThe supplied value type <" + type +
                "> contains generic parameters, so the default value cannot be retrieved");

        // If the Type is a primitive type, or if it is another publicly-visible value type (i.e. struct/enum), return a 
        //  default instance of the value type
        if (type.IsPrimitive || !type.IsNotPublic)
        {
            try
            {
                return Activator.CreateInstance(type);
            }
            catch (Exception e)
            {
                throw new ArgumentException(
                    "{" + MethodInfo.GetCurrentMethod() + "} Error:\n\nThe Activator.CreateInstance method could not " +
                    "create a default instance of the supplied value type <" + type +
                    "> (Inner Exception message: \"" + e.Message + "\")", e);
            }
        }

        // Fail with exception
        throw new ArgumentException("{" + MethodInfo.GetCurrentMethod() + "} Error:\n\nThe supplied value type <" + type + 
            "> is not a publicly-visible type, so the default value cannot be retrieved");
    }

In these examples, the GetDefault method is implemented in the static class DefaultValue. Call this method with a statement like:

        object Default = DefaultValue.GetDefault(someType);

To use the GetDefault method as an extension method for Type, call it like this:

        object Default = someType.GetDefault();

This second, Type-extension approach is a simpler client-code syntax, since it removes the need to reference the containing DefaultValue class qualifier on the call.

The above run time form of GetDefault works with identical semantics as the primitive C# 'default' keyword, and produces the same results.

To use a generic form of GetDefault, you may access the following function:

    /// <summary>
    /// [ <c>public static T GetDefault&lt; T &gt;()</c> ]
    /// <para></para>
    /// Retrieves the default value for a given Type
    /// </summary>
    /// <typeparam name="T">The Type for which to get the default value</typeparam>
    /// <returns>The default value for Type T</returns>
    /// <remarks>
    /// If a reference Type or a System.Void Type is supplied, this method always returns null.  If a value type 
    /// is supplied which is not publicly visible or which contains generic parameters, this method will fail with an 
    /// exception.
    /// </remarks>
    /// <seealso cref="GetDefault(Type)"/>
    public static T GetDefault<T>()
    {
        return (T) GetDefault(typeof(T));
    }

A call to the generic form could be something like:

        int? inDefaultVal = DefaultValue.GetDefault<int?>();

Of course, the above generic form of GetDefault is unnecessary for C#, since it works the same as default(T). It is only useful for a .NET language that does not support the 'default' keyword but which supports generic types. In most cases, the generic form is unnecessary.

A useful corollary method is one to determine whether an object contains the default value for its Type. I also rely on the following IsObjectSetToDefault method for that purpose:

    /// <summary>
    /// [ <c>public static bool IsObjectSetToDefault(this Type ObjectType, object ObjectValue)</c> ]
    /// <para></para>
    /// Reports whether a value of type T (or a null reference of type T) contains the default value for that Type
    /// </summary>
    /// <remarks>
    /// Reports whether the object is empty or unitialized for a reference type or nullable value type (i.e. is null) or 
    /// whether the object contains a default value for a non-nullable value type (i.e. int = 0, bool = false, etc.)
    /// <para></para>
    /// NOTE: For non-nullable value types, this method introduces a boxing/unboxing performance penalty.
    /// </remarks>
    /// <param name="ObjectType">Type of the object to test</param>
    /// <param name="ObjectValue">The object value to test, or null for a reference Type or nullable value Type</param>
    /// <returns>
    /// true = The object contains the default value for its Type.
    /// <para></para>
    /// false = The object has been changed from its default value.
    /// </returns>
    public static bool IsObjectSetToDefault(this Type ObjectType, object ObjectValue)
    {
        // If no ObjectType was supplied, attempt to determine from ObjectValue
        if (ObjectType == null)
        {
            // If no ObjectValue was supplied, abort
            if (ObjectValue == null)
            {
                MethodBase currmethod = MethodInfo.GetCurrentMethod();
                string ExceptionMsgPrefix = currmethod.DeclaringType + " {" + currmethod + "} Error:\n\n";
                throw new ArgumentNullException(ExceptionMsgPrefix + "Cannot determine the ObjectType from a null Value");
            }

            // Determine ObjectType from ObjectValue
            ObjectType = ObjectValue.GetType();
        }

        // Get the default value of type ObjectType
        object Default = ObjectType.GetDefault();

        // If a non-null ObjectValue was supplied, compare Value with its default value and return the result
        if (ObjectValue != null)
            return ObjectValue.Equals(Default);

        // Since a null ObjectValue was supplied, report whether its default value is null
        return Default == null;
    }

The above IsObjectSetToDefault method can either be called in its native form or accessed as a Type-class extension.

Answer 3

What do you mean by "Default Value"? All reference Types ("class") have null as default value, while all value types will have their default values according to this table.

Answer 4

How about something like...

class Program
{
  static void Main(string[] args)
  {
    PrintDefault(typeof(object));
    PrintDefault(typeof(string));
    PrintDefault(typeof(int));
    PrintDefault(typeof(int?));
  }

  private static void PrintDefault(Type type)
  {
    Console.WriteLine("default({0}) = {1}", type,
      DefaultGenerator.GetDefaultValue(type));
  }
}

public class DefaultGenerator
{
  public static object GetDefaultValue(Type parameter)
  {
    var defaultGeneratorType =
      typeof(DefaultGenerator<>).MakeGenericType(parameter);

    return defaultGeneratorType.InvokeMember(
      "GetDefault", 
      BindingFlags.Static |
      BindingFlags.Public |
      BindingFlags.InvokeMethod,
      null, null, new object[0]);
  }
}

public class DefaultGenerator<T>
{
  public static T GetDefault()
  {
    return default(T);
  }
}

It produces the following output:

default(System.Object) =
default(System.String) =
default(System.Int32) = 0
default(System.Nullable`1[System.Int32]) =

Answer 5

You could also add it as an extension method to System.Type:

public static class TypeExtensions
{
    public static object GetDefaultValue(this Type t)
    {
        if (t.IsValueType && Nullable.GetUnderlyingType(t) == null)
            return Activator.CreateInstance(t);
        else
            return null;
    }
}

Answer 6

There's really only two possibilities: null for reference types and new myType() for value types (which corresponds to 0 for int, float, etc) So you really only need to account for two cases:

object GetDefaultValue(Type t)
{
    if (t.IsValueType)
        return Activator.CreateInstance(t);

    return null;
}

(Because value types always have a default constructor, that call to Activator.CreateInstance will never fail).