In Django - Model Inheritance - Does it allow you

2019-01-04 01:45发布

I'm looking to do this:

class Place(models.Model):
   name = models.CharField(max_length=20)
   rating = models.DecimalField()

class LongNamedRestaurant(Place):  # Subclassing `Place`.
   name = models.CharField(max_length=255)  # Notice, I'm overriding `Place.name` to give it a longer length.
   food_type = models.CharField(max_length=25)

This is the version I would like to use (although I'm open to any suggestion): http://docs.djangoproject.com/en/dev/topics/db/models/#id7

Is this supported in Django? If not, is there a way to achieve similar results?

9条回答
欢心
2楼-- · 2019-01-04 01:57

No, it is not:

Field name “hiding” is not permitted

In normal Python class inheritance, it is permissible for a child class to override any attribute from the parent class. In Django, this is not permitted for attributes that are Field instances (at least, not at the moment). If a base class has a field called author, you cannot create another model field called author in any class that inherits from that base class.

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Rolldiameter
3楼-- · 2019-01-04 01:59

See https://stackoverflow.com/a/6379556/15690:

class BaseMessage(models.Model):
    is_public = models.BooleanField(default=False)
    # some more fields...

    class Meta:
        abstract = True

class Message(BaseMessage):
    # some fields...
Message._meta.get_field('is_public').default = True
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聊天终结者
4楼-- · 2019-01-04 02:01

This supercool piece of code allows you to 'override' fields in abstract parent classes.

def AbstractClassWithoutFieldsNamed(cls, *excl):
    """
    Removes unwanted fields from abstract base classes.

    Usage::
    >>> from oscar.apps.address.abstract_models import AbstractBillingAddress

    >>> from koe.meta import AbstractClassWithoutFieldsNamed as without
    >>> class BillingAddress(without(AbstractBillingAddress, 'phone_number')):
    ...     pass
    """
    if cls._meta.abstract:
        remove_fields = [f for f in cls._meta.local_fields if f.name in excl]
        for f in remove_fields:
            cls._meta.local_fields.remove(f)
        return cls
    else:
        raise Exception("Not an abstract model")

When the fields have been removed from the abstract parent class you are free to redefine them as you need.

This is not my own work. Original code from here: https://gist.github.com/specialunderwear/9d917ddacf3547b646ba

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仙女界的扛把子
5楼-- · 2019-01-04 02:02

Updated answer: as people noted in comments, the original answer wasn't properly answering the question. Indeed, only the LongNamedRestaurant model was created in database, Place was not.

A solution is to create an abstract model representing a "Place", eg. AbstractPlace, and inherit from it:

class AbstractPlace(models.Model):
    name = models.CharField(max_length=20)
    rating = models.DecimalField()

    class Meta:
        abstract = True

class Place(AbstractPlace):
    pass

class LongNamedRestaurant(AbstractPlace):
    name = models.CharField(max_length=255)
    food_type = models.CharField(max_length=25)

Please also read @Mark answer, he gives a great explanation why you can't change attributes inherited from a non-abstract class.

(Note this is only possible since Django 1.10: before Django 1.10, modifying an attribute inherited from an abstract class wasn't possible.)

Original answer

Since Django 1.10 it's possible! You just have to do what you asked for:

class Place(models.Model):
    name = models.CharField(max_length=20)
    rating = models.DecimalField()

    class Meta:
        abstract = True

class LongNamedRestaurant(Place):  # Subclassing `Place`.
    name = models.CharField(max_length=255)  # Notice, I'm overriding `Place.name` to give it a longer length.
    food_type = models.CharField(max_length=25)
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Rolldiameter
6楼-- · 2019-01-04 02:03

Pasted your code into a fresh app, added app to INSTALLED_APPS and ran syncdb:

django.core.exceptions.FieldError: Local field 'name' in class 'LongNamedRestaurant' clashes with field of similar name from base class 'Place'

Looks like Django does not support that.

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爷、活的狠高调
7楼-- · 2019-01-04 02:04

That is not possible unless abstract, and here is why: LongNamedRestaurant is also a Place, not only as a class but also in the database. The place-table contains an entry for every pure Place and for every LongNamedRestaurant. LongNamedRestaurant just creates an extra table with the food_type and a reference to the place table.

If you do Place.objects.all(), you also get every place that is a LongNamedRestaurant, and it will be an instance of Place (without the food_type). So Place.name and LongNamedRestaurant.name share the same database column, and must therefore be of the same type.

I think this makes sense for normal models: every restaurant is a place, and should have at least everything that place has. Maybe this consistency is also why it was not possible for abstract models before 1.10, although it would not give database problems there. As @lampslave remarks, it was made possible in 1.10. I would personally recommend care: if Sub.x overrides Super.x, make sure Sub.x is a subclass of Super.x, otherwise Sub cannot be used in place of Super.

Workarounds: You can create a custom user model (AUTH_USER_MODEL) which involves quite a bit of code duplication if you only need to change the email field. Alternatively you can leave email as it is and make sure it's required in all forms. This doesn't guarantee database integrity if other applications use it, and doesn't work the other way around (if you want to make username not required).

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