int main()
{
char a[7] = "Network";
return 0;
}
A string literal in C is terminated internally with a nul character. So, the above code should give a compilation error since the actual length of the string literal Network
is 8 and it cannot fit in a char[7]
array.
However, gcc (even with -Wall
) on Ubuntu compiles this code without any error or warning.
Why does gcc allow this and not flag it as compilation error?
gcc only gives a warning (still no error!) when the char array size is smaller than the string literal. For example, it warns on:
char a[6] = "Network";
[Related] Visual C++ 2012 gives a compilation error for char a[7]
:
1>d:\main.cpp(3): error C2117: 'a' : array bounds overflow
1> d:\main.cpp(3) : see declaration of 'a'
In the early days of C and Unix, memory and disk were small, so not storing the NUL byte at the end of the string was actually a technique that was used. If the string variable is seven characters long, you could store a seven-character string in it, and since seven was the max length, you knew the string ended there, even without the terminator character. This is why strncpy works the way it does.
While unwind's answer explains why
gcc
doesn't warn about this, it doesn't say what you can do about it.gcc
's-Wc++-compat
warning option will detect this particular issue with the message:That's the only option that will cause
gcc
to warn about this problem. You can write a short script to quickly grep the warning options out ofgcc
's man page, try compiling with each, and see if it complains.In general, a lint-like tool such as
splint
will warn you about all sorts of potential issues. In this case, it will say:The preffered way of declaring a string literal is usually:
Let the compiler figure it out. It's cumbersome to manually specify the array size and keep it in sync with the string literal's actual length...
So I guess GCC doesn't really bother with anything more than a warning.
Initializing a char array with a string literal that is larger than it is fine in C, but wrong in C++. That explains the difference in behavior between gcc and VC++.
You would get no error if you compiled the same as a C file with VC++. And you would get an error if you compiled it as a C++ file with g++.
The C standard says:
(Section 6.7.9 of the C11 draft standard, actual wording in final standard might be different.)
This means that it's perfectly correct to drop the termination character if the array doesn't have room for it. It's maybe unexpected, but it's exactly how the language is supposed to work, and a (at least to me) well-known feature.
On the contrary, the C++ standard says:
(8.5.2 of the C++ 2011 draft n3242.)