In-memory size of a Python structure

Question

Is there a reference for the memory size of Python data stucture on 32- and 64-bit platforms?

If not, this would be nice to have it on SO. The more exhaustive the better! So how many bytes are used by the following Python structures (depending on the len and the content type when relevant)?

• int
• float
• reference
• str
• unicode string
• tuple
• list
• dict
• set
• array.array
• numpy.array
• deque
• new-style classes object
• old-style classes object
• ... and everything I am forgetting!

(For containers that keep only references to other objects, we obviously do not want to count the size of the item themselves, since it might be shared.)

Furthermore, is there a way to get the memory used by an object at runtime (recursively or not)?

Answer 1

I've been happily using pympler for such tasks. It's compatible with many versions of Python -- the asizeof module in particular goes back to 2.2!

For example, using hughdbrown's example but with from pympler import asizeof at the start and print asizeof.asizeof(v) at the end, I see (system Python 2.5 on MacOSX 10.5):

$ python pymp.py 
set 120
unicode 32
tuple 32
int 16
decimal 152
float 16
list 40
object 0
dict 144
str 32

Clearly there is some approximation here, but I've found it very useful for footprint analysis and tuning.

Answer 2

Also you can use guppy module.

>>> from guppy import hpy; hp=hpy()
>>> hp.heap()
Partition of a set of 25853 objects. Total size = 3320992 bytes.
 Index  Count   %     Size   % Cumulative  % Kind (class / dict of class)
     0  11731  45   929072  28    929072  28 str
     1   5832  23   469760  14   1398832  42 tuple
     2    324   1   277728   8   1676560  50 dict (no owner)
     3     70   0   216976   7   1893536  57 dict of module
     4    199   1   210856   6   2104392  63 dict of type
     5   1627   6   208256   6   2312648  70 types.CodeType
     6   1592   6   191040   6   2503688  75 function
     7    199   1   177008   5   2680696  81 type
     8    124   0   135328   4   2816024  85 dict of class
     9   1045   4    83600   3   2899624  87 __builtin__.wrapper_descriptor
<90 more rows. Type e.g. '_.more' to view.>

And:

>>> hp.iso(1, [1], "1", (1,), {1:1}, None)
Partition of a set of 6 objects. Total size = 560 bytes.
 Index  Count   %     Size   % Cumulative  % Kind (class / dict of class)
     0      1  17      280  50       280  50 dict (no owner)
     1      1  17      136  24       416  74 list
     2      1  17       64  11       480  86 tuple
     3      1  17       40   7       520  93 str
     4      1  17       24   4       544  97 int
     5      1  17       16   3       560 100 types.NoneType

Answer 3

The recommendation from an earlier question on this was to use sys.getsizeof(), quoting:

>>> import sys
>>> x = 2
>>> sys.getsizeof(x)
14
>>> sys.getsizeof(sys.getsizeof)
32
>>> sys.getsizeof('this')
38
>>> sys.getsizeof('this also')
48

You could take this approach:

>>> import sys
>>> import decimal
>>> 
>>> d = {
...     "int": 0,
...     "float": 0.0,
...     "dict": dict(),
...     "set": set(),
...     "tuple": tuple(),
...     "list": list(),
...     "str": "a",
...     "unicode": u"a",
...     "decimal": decimal.Decimal(0),
...     "object": object(),
... }
>>> for k, v in sorted(d.iteritems()):
...     print k, sys.getsizeof(v)
...
decimal 40
dict 140
float 16
int 12
list 36
object 8
set 116
str 25
tuple 28
unicode 28

---

2012-09-30

python 2.7 (linux, 32-bit):

decimal 36
dict 136
float 16
int 12
list 32
object 8
set 112
str 22
tuple 24
unicode 32

python 3.3 (linux, 32-bit)

decimal 52
dict 144
float 16
int 14
list 32
object 8
set 112
str 26
tuple 24
unicode 26

---

2016-08-01

OSX, Python 2.7.10 (default, Oct 23 2015, 19:19:21) [GCC 4.2.1 Compatible Apple LLVM 7.0.0 (clang-700.0.59.5)] on darwin

decimal 80
dict 280
float 24
int 24
list 72
object 16
set 232
str 38
tuple 56
unicode 52

Answer 4

When you use the dir([object]) built-in function, you can the sizeof built-in function.

>>> a = -1
>>> a.__sizeof__()
24

Answer 5

These answers all collect shallow size information. I suspect that visitors to this question will end up here looking to answer the question, "How big is this complex object in memory?"

There's a great answer here: https://goshippo.com/blog/measure-real-size-any-python-object/

The punchline:

import sys

def get_size(obj, seen=None):
    """Recursively finds size of objects"""
    size = sys.getsizeof(obj)
    if seen is None:
        seen = set()
    obj_id = id(obj)
    if obj_id in seen:
        return 0
    # Important mark as seen *before* entering recursion to gracefully handle
    # self-referential objects
    seen.add(obj_id)
    if isinstance(obj, dict):
        size += sum([get_size(v, seen) for v in obj.values()])
        size += sum([get_size(k, seen) for k in obj.keys()])
    elif hasattr(obj, '__dict__'):
        size += get_size(obj.__dict__, seen)
    elif hasattr(obj, '__iter__') and not isinstance(obj, (str, bytes, bytearray)):
        size += sum([get_size(i, seen) for i in obj])
    return size

Used like so:

In [1]: get_size(1)
Out[1]: 24

In [2]: get_size([1])
Out[2]: 104

In [3]: get_size([[1]])
Out[3]: 184

If you want to know Python's memory model more deeply, there's a great article here that has a similar "total size" snippet of code as part of a longer explanation: https://code.tutsplus.com/tutorials/understand-how-much-memory-your-python-objects-use--cms-25609

Answer 6

Try memory profiler. memory profiler

Line #    Mem usage  Increment   Line Contents
==============================================
     3                           @profile
     4      5.97 MB    0.00 MB   def my_func():
     5     13.61 MB    7.64 MB       a = [1] * (10 ** 6)
     6    166.20 MB  152.59 MB       b = [2] * (2 * 10 ** 7)
     7     13.61 MB -152.59 MB       del b
     8     13.61 MB    0.00 MB       return a