How to make this jQuery animation code loop foreve

Question

i am trying to create a loop of text animations over a slider... i tried loop but it didnt work.. Can you please tell me how do i loop this script forever..thanks

<script>
$(document).ready(function() {
    $("#header").hide();
    var headerOne='I';
    var headerTwo='Am'; 
    var headerThree='So';
    var headerFour='Cool';
        $("#header").html(headerOne);
    $("#header").fadeIn(1000);
    $('#header').delay(1000).fadeOut(1000,function(){
    $(this).html(headerTwo).fadeIn(1000);
     $('#header').delay(1000).fadeOut(1000,function(){
     $(this).html(headerThree).fadeIn(1000);
     $('#header').delay(1000).fadeOut(1000,function(){
     $(this).html(headerFour).fadeIn(1000).delay(1000).fadeOut(1000);       
      });
        });
    });

});
</script>

Thanks!

Answer 1

Create a recursive and self-executing function and use it as the final callback:

p.s. Took the liberty to clean up your code.

$(function () {
    (function repeat() {
        var header = $("#header"),
            headerOne = 'I',
            headerTwo = 'Am',
            headerThree = 'So',
            headerFour = 'Cool';

        header.text(headerOne)
            .fadeIn(1000)
            .delay(1000)
            .fadeOut(1000, function () {
            header.text(headerTwo)
                .fadeIn(1000)
                .delay(1000)
                .fadeOut(1000, function () {
                header.text(headerThree)
                    .fadeIn(1000)
                    .delay(1000).fadeOut(1000, function () {
                    header.text(headerFour)
                        .fadeIn(1000)
                        .delay(1000)
                        .fadeOut(1000, repeat);
                });
            });
        });
    })();
});

Answer 2

If you clean your code a bit. You can realize that setInterval is not needed. Simply make use of the last callback to repeat the animation.

$(function () {
    var $header = $("#header");
    var header = ['I', 'Am', 'So', 'Cool'];
    var position = -1;

    !function loop() {
        position = (position + 1) % header.length;
        $header
            .html(header[position])
            .fadeIn(1000)
            .delay(1000)
            .fadeOut(1000, loop);
    }();
});

See it here.

Answer 3

You can use recurence, the last fadeOut will execute repeat function when finish.

function repeat() {
    $("#header").hide();
    var headerOne='I';
    var headerTwo='Am'; 
    var headerThree='So';
    var headerFour='Cool';
    $("#header").html(headerOne);
    $("#header").fadeIn(1000);
    $('#header').delay(1000).fadeOut(1000,function() {
        $(this).html(headerTwo).fadeIn(1000);
        $('#header').delay(1000).fadeOut(1000,function() {
            $(this).html(headerThree).fadeIn(1000);
            $('#header').delay(1000).fadeOut(1000,function() {
                $(this).html(headerFour).fadeIn(1000).delay(1000).
                    fadeOut(1000, repeat); 
            });
        });
    });
}

$(document).ready(function() {
    repeat();
});