Python super(Class, self).method vs super(Parent,

Question

This question is derive from the following question, let's say class B extends class A

class A(object):
  def do_work(self):
    print 123

class B(A):
  def do_work(self):
    super(B,self).do_work() # versus the next statement
    super(A,self).do_work() # what's the difference?

Answer 1

super(B,self).do_work()

will call the do_work function as seen by the parent class of B - that is, A.do_work.

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super(A,self).do_work()

will call the do_work function as seen by the parent class of A - that is, object.do_work (which probably doesn't exist, and thus would likely raise an exception).