PHP Zend Framework - How to Get Request URI Fragme

2019-02-13 12:42发布

Say e.g. i have a URI http://127.0.0.1/somecontroller/someaction#12345 that takes me to the someAction() action of the someController controller. From there, i am able to retrieve the Request object via $this->getRequest().

i am also able to retrieve various information regarding the URI from the Request object.

But, how can i retrieve the fragment (i.e. the "12345" part after the # in the e.g.)? Neither getRequestUri() nor getParams() turn up the fragment part.

Thanks!

4条回答
Summer. ? 凉城
2楼-- · 2019-02-13 13:16

The fragment part of the URL is never sent to the server via GET requests (or any kind of HTTP request for that matter), the only way you can get it is if you write a Javascript snippet that parses the URL and sends the fragment back to the server via Ajax for instance.

This can't be done with PHP alone.

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3楼-- · 2019-02-13 13:32

According to HTTP protocol specification, the fragment part is ignored. However, browsers do support redirects with hash.

If you generate hashes automatically, you may pass the id as the request parameter: http://127.0.0.1/somecontroller/someaction/id/12345/#12345

and then:

$this->getRequest()->getParam('id')

But this will hot handle the case with the hash only, e.g. when user enters the URL manually.

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闹够了就滚
4楼-- · 2019-02-13 13:38

Couldn't you use the php function(s) explode("#",$_SERVER['REQUEST_URI'])? Maybe I've misunderstood the question.

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【Aperson】
5楼-- · 2019-02-13 13:39

You cannot use:

explode("#",$_SERVER['REQUEST_URI'])

because when you call $_SERVER['REQUEST_URI'], you never get the word after #. For example your link www.example.com/about#test, and when you call $_SERVER['REQUEST_URI'], you just get www.example.com/about.

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