Xcode C++ :: Duplicate Symbols for Architecture x8

2019-02-13 09:16发布

I am new to Xcode and when I build the following code (an MWE), I get the following error

ld: 3 duplicate symbols for architecture x86_64 clang: error: linker command failed with exit code 1 (use -v to see invocation)

I have three files as following;

main.cpp

#include "B.cpp"
int main() {
  square(5);
  return 0;
}

B.cpp

#include "A.cpp"

void square(int n){
  display(n*n);
}

A.cpp

#include <iostream>
using namespace std;

void display(int num){
  cout<<num;
}

I have tried different methods mentioned on stack overflow like change "Build Active Architecture Only" to "Yes" and some others but the error still persists.

1条回答
祖国的老花朵
2楼-- · 2019-02-13 09:53

Problem is that main.cpp has included B.cpp and A.cpp. In your build process, you are also compiling B.cpp and A.cpp and trying to link B.o and A.o alongwith main.o.

Linking B.o and A.o causes symbols display and square to be defined multiple times. display is defined 3 times and square defined 2 times.

You just compile and build main.cpp. Do not build A.cpp and B.cpp.

Second way is that make A.cpp and B.cpp to A.h and B.h and functions inline. So, they will be compiled only once.

Third way, do not include B.cpp in main.cpp. Just put function declaration instead of inclusion.

//main.cpp

void square(int);

int main() {
  square(5);
  return 0;
}

Generally, function declarations are put in header files. If that is required in multiple cases, make a header file.

查看更多
登录 后发表回答