How do I round a double to two decimal places in J

Question

This is what I did to round a double to 2 decimal places:

amount = roundTwoDecimals(amount);

public double roundTwoDecimals(double d) {
    DecimalFormat twoDForm = new DecimalFormat("#.##");
    return Double.valueOf(twoDForm.format(d));
}

This works great if the amount = 25.3569 or something like that, but if the amount = 25.00 or the amount = 25.0, then I get 25.0! What I want is both rounding as well as formatting to 2 decimal places.

Answer 1

Use a digit place holder (0), as with '#' trailing/leading zeros show as absent:

DecimalFormat twoDForm = new DecimalFormat("#.00");

Answer 2

If you want the result to two decimal places you can do

// assuming you want to round to Infinity.
double tip = (long) (amount * percent + 0.5) / 100.0; 

This result is not precise but Double.toString(double) will correct for this and print one to two decimal places. However as soon as you perform another calculation, you can get a result which will not be implicitly rounded. ;)

Answer 3

You can use Apache Commons Math:

Precision.round(double x, int scale)

source: http://commons.apache.org/proper/commons-math/apidocs/org/apache/commons/math3/util/Precision.html#round(double,%20int)

Answer 4

DecimalFormat df = new DecimalFormat("###.##");
double total = Double.valueOf(val);

Answer 5

First declare a object of DecimalFormat class. Note the argument inside the DecimalFormat is #.00 which means exactly 2 decimal places of rounding off.

private static DecimalFormat df2 = new DecimalFormat("#.00");

Now, apply the format to your double value:

double input = 32.123456;
System.out.println("double : " + df2.format(input)); // Output: 32.12

Note in case of double input = 32.1;

Then the output would be 32.10 and so on.

Answer 6

You can use org.apache.commons.math.util.MathUtils from apache common

double round = MathUtils.round(double1, 2, BigDecimal.ROUND_HALF_DOWN);