Why doesn't Perl support interpolation of hash

2019-02-13 02:41发布

#!/usr/bin/perl
use warnings;

my %hash=("no1"=>1, 
        "no2"=>2,
      );

print %hash; #Prints no11no22
print "%hash"; #Prints %hash

Why doesn't Perl support interpolation of a hash within double quotes? It supports interpolation for scalars ($), arrays (@) then why not for hashes (%)?

3条回答
Luminary・发光体
2楼-- · 2019-02-13 03:11

To quote Nathan Torkington: "The big problem is that % is heavily used in double-quoted strings with printf." More information is here.

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萌系小妹纸
3楼-- · 2019-02-13 03:20

How should a hash stringify? Scalars are obvious and arrays too. But what should a hash be? How useful will such a stringification be? Is it more or less useful than being able to use a % character unescaped in an interpolating string? Is it worth the amount of work it will take to fix all of the code that uses % in interpolated strings today?

If you can come up with good answers to these questions, then I am sure P5P would be willing to listen to them.

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Anthone
4楼-- · 2019-02-13 03:33

Not really an answer to the "why", but I thought I would point out various answers to the "how".

One could, of course, try:

#!/usr/bin/perl
use warnings; use strict;

my %hash = (
    "no1" => 1,
    "no2" => 2,
);

print "@{[ %hash ]}\n";

But, I don't know what use that would be.

If you want to dump the contents of a hash or any other complicated data structure, use Data::Dumper or YAML or JSON depending on your use case.

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