This question already has an answer here:
I'd like to give a keyword, find the line where this keyword aṕpears in a file and erase the entire line.
This is what I got but it is not working as it should:
KEYWORD='domain.com'
cat /etc/hosts | grep -v "$KEYWORD" > /etc/hosts
UPDATE
This is what worked for me:
sed -i_bak -e '/domain\.com/d' /etc/hosts
However, as I had two lines with "domain.com", is there a way to tell sed to erase only the line where the exact keyword "domain.com" appears
This is the original content of /etc/hosts:
127.0.0.1 localhost localhost.localdomain
222.111.22.222 hvn.domain.com
222.111.22.222 domain.com
Here's how it end up after the command sed -i_bak -e '/domain\.com/d' /etc/hosts
:
127.0.0.1 localhost localhost.localdomain
I tried sed -i_bak -e '/\<namourphoto\.com\.br\>/d' ~/Desktop/hosts
but it didn't work.
CONCLUSION
This is the code I came up with (based on the help the fine folks have given me):
D=domain.com
DOMAIN=`echo "$D" | sed 's/\./\\\\./g'`
sed -i_bak -e "/[\t]$DOMAIN/d" /etc/hosts
Note that:
I am counting that there is always a tab before the domain to be erased
I am automatically escaping the dots of the domain name.
Use the stream editor, sed:
The above will delete lines containing culpa in test.txt. It will create a backup of the original (named test.txt.bak) and will modify the original file in-place.
If you want to only delete last line of your example file
Pipe it to another file, not the same one that you're reading from, and be careful with the useless use of
cat
.Apart from the fine answer given regarding sed, you can also use Perl and a little improved regex to solve this:
Notice I'm considering
domain.com
will be isolated by space characters (tabs or spaces, and so on), and that nothing but zero or more spaces will appear after it until the newline. Similarly to-i
in sed,-i.old
in perl sets the$^I
variable, and your original file will receive the changes while a copy will be kept under the old name and a.old
appended.