jQuery SVG, why can't I addClass?

2018-12-31 05:13发布

I am using jQuery SVG. I can't add or remove a class to an object. Anyone know my mistake?

The SVG:

<rect class="jimmy" id="p5" x="200" y="200" width="100" height="100" />

The jQuery that won't add the class:

$(".jimmy").click(function() {
    $(this).addClass("clicked");
});

I know the SVG and jQuery are working together fine because I can target the object and fire an alert when it's clicked:

$(".jimmy").click(function() {
    alert('Handler for .click() called.');
});

15条回答
余生请多指教
2楼-- · 2018-12-31 05:22

If you have dynamic classes or don't know what classes could be already applied then this method I believe is the best approach:

// addClass
$('path').attr('class', function(index, classNames) {
    return classNames + ' class-name';
});

// removeClass
$('path').attr('class', function(index, classNames) {
    return classNames.replace('class-name', '');
});
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心情的温度
3楼-- · 2018-12-31 05:24

There is element.classList in the DOM API that works for both HTML and SVG elements. No need for jQuery SVG plugin or even jQuery.

$(".jimmy").click(function() {
    this.classList.add("clicked");
});
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素衣白纱
4楼-- · 2018-12-31 05:24

Just add the missing prototype constructor to all SVG nodes:

SVGElement.prototype.hasClass = function (className) {
  return new RegExp('(\\s|^)' + className + '(\\s|$)').test(this.getAttribute('class'));
};

SVGElement.prototype.addClass = function (className) { 
  if (!this.hasClass(className)) {
    this.setAttribute('class', this.getAttribute('class') + ' ' + className);
  }
};

SVGElement.prototype.removeClass = function (className) {
  var removedClass = this.getAttribute('class').replace(new RegExp('(\\s|^)' + className + '(\\s|$)', 'g'), '$2');
  if (this.hasClass(className)) {
    this.setAttribute('class', removedClass);
  }
};

You can then use it this way without requiring jQuery:

this.addClass('clicked');

this.removeClass('clicked');

All credit goes to Todd Moto.

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几人难应
5楼-- · 2018-12-31 05:29

One workaround could be to addClass to a container of the svg element:

$('.svg-container').addClass('svg-red');
.svg-red svg circle{
    fill: #ED3F32;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="svg-container">
  <svg height="40" width="40">
      <circle cx="20" cy="20" r="20"/>
  </svg>
</div>

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怪性笑人.
6楼-- · 2018-12-31 05:31

After loading jquery.svg.js you must load this file: http://keith-wood.name/js/jquery.svgdom.js.

Source: http://keith-wood.name/svg.html#dom

Working example: http://jsfiddle.net/74RbC/99/

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ら面具成の殇う
7楼-- · 2018-12-31 05:31

jQuery does not support the classes of SVG elements. You can get the element directly $(el).get(0) and use classList and add / remove. There is a trick with this too in that the topmost SVG element is actually a normal DOM object and can be used like every other element in jQuery. In my project I created this to take care of what I needed but the documentation provided on the Mozilla Developer Network has a shim that can be used as an alternative.

example

function addRemoveClass(jqEl, className, addOrRemove) 
{
  var classAttr = jqEl.attr('class');
  if (!addOrRemove) {
    classAttr = classAttr.replace(new RegExp('\\s?' + className), '');
    jqEl.attr('class', classAttr);
  } else {
    classAttr = classAttr + (classAttr.length === 0 ? '' : ' ') + className;
    jqEl.attr('class', classAttr);
  }
}

An alternative all tougher is to use D3.js as your selector engine instead. My projects have charts that are built with it so it's also in my app scope. D3 correctly modifies the class attributes of vanilla DOM elements and SVG elements. Though adding D3 for just this case would likely be overkill.

d3.select(el).classed('myclass', true);
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