How to write a like query in HQL [duplicate]

Question

This question already has an answer here:

• Using LIKE % in Hibernate 3 answers

I want to perform search for a particular string that is starting with a particular alphabet. So, for example if the starting alphabet is 'A' den it should produce a result which will contain all the strings with alphabet 'A'.

How do I achieve this ?

My query is as shown below

Query qry = session.createQuery("From RegistrationBean as rb where rb."+searchCriteria+"  like %?%");
qry.setString(0,searchField);

Answer 1

You can use criteria for using like

session = sessionFactory.openSession();
Criteria query = session.createCriteria(Pojo.class);
query.add(Restrictions.like("column", "a", MatchMode.START));

It will give you the list of string which start by alpha-bate 'a'.

Answer 2

Change your query to this:

Query qry = session.createQuery("From RegistrationBean as rb where rb."+searchCriteria+"  like ?");
qry.setString(0, "%"+searchField+"%");

Answer 3

Query qry = session.createQuery("From RegistrationBean as rb where rb."+searchCriteria+" like :sf");
qry.setString("sf",'%'+searchField+'%');

The above thing worked for me :)

Answer 4

Change to

Query qry = session.createQuery("From RegistrationBean as rb where rb ";
if (searchField != null)
{
    qry = qry + " where rb.searchCriteria like :searchField ";
}
if ( searchField!= null)
{
    query.setString("searchField","%"+searchField+"%");
}

Answer 5

This way

createQuery("from RegistrationBean as rb where rb.:searchCriteria like '%:searchField%'");