Alamofire Swift 3.0 Extra argument in call

Question

I have migrated my project to Swift 3 (and updated Alamofire to latest Swift 3 version with pod 'Alamofire', '~> 4.0' in the Podfile).

I now get an "Extra argument in call" error on every Alamofire.request. Eg:

let patientIdUrl = baseUrl + nextPatientIdUrl
Alamofire.request(.POST, patientIdUrl, parameters: nil, headers: nil, encoding: .JSON)

Can anybody tell me why ?

Answer 1

If you have added Alamofire files locally then don't use "Alamofire" before request

let apipath = “your api URL”    
    request(apipath, method: .post, parameters: parameters, encoding: URLEncoding.default, headers: nil).responseJSON { response in switch(response.result) {
            case .success(_):
                do {
                    let JSON = try JSONSerialization.jsonObject(with: response.data! as Data, options:JSONSerialization.ReadingOptions(rawValue: 0))

                    guard let JSONDictionary: NSDictionary = JSON as? NSDictionary else {
                        print("Not a Dictionary")
                        return
                    }

                    print("Post Response : \(JSONDictionary)")
                }
                catch let JSONError as NSError {
                    print("\(JSONError)")
                }
                break
            case .failure(_):
                print("failure Http: \(String(describing: response.result.error?.localizedDescription))")
                break
            }
    }

Answer 2

This one worked for me.
No need to remove encoding parameter

Swift 3.x / 4.x

Alamofire.request("https://yourServiceURL.com", method: .post, parameters: parameters, encoding: JSONEncoding.default, headers: nil).responseJSON { (response:DataResponse<Any>) in

        switch(response.result) {
        case .success(_):
            if let data = response.result.value{
                print(response.result.value)
            }
            break

        case .failure(_):
            print(response.result.error)
            break

        }
    }

and make sure that the parameters are of type

[String:Any]?

In case of Get

Alamofire.request("https://yourGetURL.com", method: .get, parameters: ["":""], encoding: URLEncoding.default, headers: nil).responseJSON { (response:DataResponse<Any>) in

        switch(response.result) {
        case .success(_):
            if let data = response.result.value{
                print(response.result.value)
            }
            break

        case .failure(_):
            print(response.result.error)
            break

        }
    }

Even works with

JSONEncoding.default 

For Headers

If you are passing headers, make sure their type should be [String:String]

Go through the Parameter Encoding Link https://github.com/Alamofire/Alamofire/blob/master/Documentation/Alamofire%204.0%20Migration%20Guide.md#parameter-encoding-protocol

Answer 3

I ran into this same Extra argument 'method' in call error when my URL variable was out of scope.

In your case, please make sure both baseUrl and nextPatientIdUrl are in scope when they are being used Alamofire.request(patientIdUrl,..) method.

Hopefully this resolves your issue. Thanks You!

Answer 4

I just resolved the same problem as you have. The problem is I have imported Alamofire in the header, so I just remove the Alamofire when call request. Like that:

request(.POST, patientIdUrl, parameters: nil, headers: nil, encoding: .JSON)

I hope it can help you.

Answer 5

I fixed this issue this way:

Just remove extra parameters, just parameters, encoding and headers, if these parameters are nil you can remove then and leave this way,

Alamofire.request(yourURLString, method: .post)

Answer 6

I copy this code from Alamofire,create a URLRequest and used Alamofire.request(URLRequest) method, avoid this error

originalRequest = try URLRequest(url: url, method: method, headers: headers)
let encodedURLRequest = try encoding.encode(originalRequest!, with: parameters)