Why Template “Spring MVC Project” in “SpringSource

Question

When Im create Spring MVC Template project in SpringSource Tool and try to Run on the Tomcat server I have this error:

WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/test/] in DispatcherServlet with name 'appServlet'.

This is default: /test/src/main/java/ru/test/test/HomeController.java

@Controller
public class HomeController {

    private static final Logger logger = LoggerFactory
            .getLogger(HomeController.class);

    /**
     * Simply selects the home view to render by returning its name.
     */
    @RequestMapping(value = "/", method = RequestMethod.GET)
    public String home(Locale locale, Model model) {
        logger.info("Welcome home! the client locale is " + locale.toString());

        Date date = new Date();
        DateFormat dateFormat = DateFormat.getDateTimeInstance(DateFormat.LONG,
                DateFormat.LONG, locale);

        String formattedDate = dateFormat.format(date);

        model.addAttribute("serverTime", formattedDate);

        return "home";
    }

}

This is default: /test/src/main/webapp/WEB-INF/web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

    <!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/root-context.xml</param-value>
    </context-param>

    <!-- Creates the Spring Container shared by all Servlets and Filters -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <!-- Processes application requests -->
    <servlet>
        <servlet-name>appServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>appServlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

</web-app>

This is default /test/src/main/webapp/WEB-INF/spring/appServlet/servlet-context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

    <!-- Enables the Spring MVC @Controller programming model -->
    <annotation-driven />

    <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
    <resources mapping="/resources/**" location="/resources/" />

    <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
    <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <beans:property name="prefix" value="/WEB-INF/views/" />
        <beans:property name="suffix" value=".jsp" />
    </beans:bean>

    <context:component-scan base-package="ru.test.test" />



</beans:beans>

Default /test/src/main/webapp/WEB-INF/spring/root-context.xml is empty

Answer 1

After you create your Spring Template MVC Project in Eclipse, you have to build it MANUALLY, before running it on a server.

Answer 2

Found a solution!

When you start creating the project, you have to define this. (pay attention to the third level superapp )

In order to get to the app, the url is http://localhost:8080/superapp

That's worked for me

Answer 3

It looks to me like the url you're trying to hit is "/test/" and the web.xml is only mapping "/". You could change that to "/*" if you want spring to handle all urls, and then you'd also have to change your home controller to be "/test".

Or you could just hit the url "http://localhost:8080/" which is the root URL that you have mapped to the home controller.

Answer 4

I was getting the exact same issue and I solved it. Basically, when the Spring MVC Project gets created, Eclipse does not configure src/main/webapp as a source directory by default. It likely needs to be a source directory because then Eclipse will treat the files differently when it builds it.

Right clicking on the 'webapp' folder and clicking 'Build Path -> Use as Source Folder' solved this issue for me. The other comments here are wrong: I did NOT have to change my RequestMapping or servlet url-pattern. '/' for both worked for my 'localhost:8080/test/'.