This question already has an answer here:
I have just started to teach myself x86 assembly on linux from these video tutorials. Early on it teaches you how to use the write sys-call to print a string that is stored in the data section. Is it possible to use the write syscall to print a string that is stored on the stack. Here is the code I wrote to try and do this which doesn't seem to work.
.data
abc:
.asciz "ABC"
.text
.globl _start
_start:
pushq %rbp
movq %rsp, %rbp
subq $32, %rsp
leaq -32(%rbp), %rdi
movb $65, (%rdi) #move 'A' on to stack
addq $1, %rdi
movb $66, (%rdi) #move 'B' on to stack
addq $1, %rdi
movb $67, (%rdi) #move 'C' on to stack
addq $1, %rdi
movb $0, (%rdi) #Null terminate
movq $4, %rax #4 is write syscall
movq $1, %rbx #1 for stdout
movq %rsp, %rcx #pointer to ABC string on stack
movq $3, %rdx #length of string
int $0x80
movq $1, %rax #exit syscall
xorq %rbx, %rbx
int $0x80
This program just runs and exits without printing ABC, but if I pass the string stored in the data segment, ABC is printed. Am I doing something wrong or can you not do it this way. Any help apprecitated.
Your syscall numbers seem WAY off.
From your use of
movq
and the "r" registers, I can guess you are trying on x86-64. Taking a look at/usr/include/asm/unistd_64.h
, I can see the following:strace
agrees with me:Note that the parameters are also way off. You are also using the wrong registers for the rest of the parameters. The calling convention on x86-64, AFAIK, uses the following registers for the parameters, in this order:
rdi
,rsi
,rdx
,r10
,r8
,r9
.Perhaps you are trying to do syscalls on x86-64 the way they are done on i386 and expecting it to be the same?