Here is a simple example of some code that compiles using Java 6, but does not compile in Java 7.
public class Test<T extends Test> {
private final int _myVar;
public Test(int myVar) {
_myVar = myVar;
}
public int get(TestContainer<T> container){
T t = container.get();
return t._myVar;
}
private static class TestContainer<T extends Test> {
private final T _test;
private TestContainer(T test) {
_test = test;
}
public T get(){
return _test;
}
}
}
In Java 7, it fails to compile in the get(TestContainer<T> container)
method, with the error:
error: _myVar has private access in Test
I don't understand why this no longer compiles - in my mind it should. The variable t
is of type T
, which must extend Test
. It's trying to access the field _myVar
of a instance of Test
from within the class Test
.
Indeed, if I change the method get(TestContainer<T> container)
to the following, it compiles (with no warnings):
public int get(TestContainer<T> container){
Test t = container.get();
return t._myVar;
}
- Why does this no longer compile?
- Was this a bug in Java 6? If so why?
- Is this a bug in Java 7?
I've had a google and searched in the Oracle bug database, but haven't found anything on this...
See @pingw33n's comment for the answer, but the way to fix this is to remove the generic parameters on the nested class. Unless you have a use case where the inner and outer T's can be different, they are redundant. All they are doing is causing this grief.
From my understanding of that JLS part, your case with a type variable
<T extends Test>
creates the following intersection:Therefore when you access members of the type
T
you actually access members of the intersection typeI
. Since private members are never inherited by subtypes accessing such member fails with compile-error. On the other hand access to package-private (default) and protected members is allowed by the fact the intersection isA workaround for this is to cast the generic instance to the concrete supertype that declares the private field, e.g.