Using Html.BeginForm with querystring

2019-02-07 23:05发布

My url looks like this:

customer/login?ReturnUrl=home

In the login view, I have used this pattern of code which works fine.

@using(Html.BeginForm())
{
   ...
}

This magically generates following html

<form action="customer/login?ReturnUrl=home" method="post">

But now, I need to add an attribute (e.g., data-id="something") in the form. How can I do that? If I don't have any query string, I know I can do something like this:

@using(Html.BeginForm(action, controller, FormMethod.Post, 
                      new { data_id="something" }))

But don't know how to add querystring which should be in html:

<form action="customer/login?ReturnUrl=home" method="post" data-id="something">

I thought about using <form> directly but don't know how to specify querystring which is variable. And I have no idea how to achieve it with Html.BeginForm. Any tip would be appreciated.

RESOLUTION:

For now, I used <form> with following hint How to get current url value in View. The resulting view looks like

<form action="@Request.Url.PathAndQuery" data-id="something" method="POST">

But it would be nice to have an overloaded method of BeginForm for this.

7条回答
够拽才男人
2楼-- · 2019-02-07 23:17

Here's The way that worked for me

Html.BeginForm("Profile", "Partner", routeValues: new {id=Partner.partner_id},method:FormMethod.Post)

It was almost like there was a problem with overloading the method, but by specifying what things are, it seems to work fine...

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三岁会撩人
3楼-- · 2019-02-07 23:21

I guess this doesn't directly answer the question, but why not just use a plain old form tag?

 <form action='customer/login?ReturnUrl=@Request.QueryString["ReturnUrl"]' method="post" data-id="something">

Alternatively, you can create a custom HtmlHelperExtension that renders a form with path and querystring. In this HtmlHelperExtension you can iterate through your querystring values and populate the routeValueDictionary which you then pass to a Html.BeginForm constructor.

If you don't want something so extensible you can just use the overloaded constructor of Html.BeginForm using @Html.BeginForm("login", "customer", new {ReturnUrl = @Request.QueryString["ReturnUrl"]},FormMethod.Post, new {data-id="something"});

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放荡不羁爱自由
4楼-- · 2019-02-07 23:21

To create a RouteValueDictionary from the querystring:

RouteValueDictionary queryStringDictionary = new RouteValueDictionary(Request.QueryString.AllKeys.ToDictionary(key => key, key => (object)Request.QueryString[key]));

Then you can use it with Html.BeginForm:

Html.BeginForm(null, null, queryStringDictionary, FormMethod.Post, new Dictionary<string, object> { { "autocomplete", "off" } })
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家丑人穷心不美
5楼-- · 2019-02-07 23:31

This works for me :

@using (Html.BeginForm("index", "Photos", routeValues: new { user = pUser, album = pAlbum, }, method: FormMethod.Get))

Explicit route values and method is what is required...

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狗以群分
6楼-- · 2019-02-07 23:33

using Reflector to look at the code,

BeginForm() will pass directly the rawUrl over to the final Form. Any other overloads on BeginForm will go through a helper utility which will strip the query string.

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The star\"
7楼-- · 2019-02-07 23:38

Just incase you wanted to add other attributes as well. use below code

@using (Html.BeginForm("actionName", "controllerName", routeValues: new { lang = "en" }, method:FormMethod.Post, htmlAttributes: new { @class= "my-form", enctype = "multipart/form-data" }))
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