Is there an O(n) integer sorting algorithm?

2019-01-03 09:40发布

The last week I stumbled over this paper where the authors mention on the second page:

Note that this yields a linear running time for integer edge weights.

The same on the third page:

This yields a linear running time for integer edge weights and O(m log n) for comparison-based sorting.

And on the 8th page:

In particular, using fast integer sorting would probably accelerate GPA considerably.

Does this mean that there is a O(n) sorting algorithm under special circumstances for integer values? Or is this a specialty of graph theory?

PS:
It could be that reference [3] could be helpful because on the first page they say:

Further improvements have been achieved for [..] graph classes such as integer edge weights [3], [...]

but I didn't have access to any of the scientific journals.

6条回答
淡お忘
2楼-- · 2019-01-03 10:19

While not very practical (mainly due to the large memory overhead), I thought I would mention Abacus (Bead) Sort as another interesting linear time sorting algorithm.

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爱情/是我丢掉的垃圾
3楼-- · 2019-01-03 10:23

Adding a little more detail - Practically the best sorting algorithm till date is not O(n) , but 0(n\sqrt {\log \log n}) .

You can check more details about this algo in the paper : http://dl.acm.org/citation.cfm?id=652131

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Explosion°爆炸
4楼-- · 2019-01-03 10:33

Yes, radix sort and counting sort are O(N). They are NOT comparison-based sorts, which have been proven to have Ω(N log N) lower bound.

To be precise, radix sort is O(kN), where k is the number of digits in the values to be sorted. Counting sort is O(N + k), where k is the range of the numbers to be sorted.

There are specific applications where k is small enough that both radix sort and counting sort exhibit linear-time performance in practice.

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可以哭但决不认输i
5楼-- · 2019-01-03 10:37

Comparison sorts must be at least Ω(n log n) on average.

However, counting sort and radix sort scale linearly with input size – because they are not comparison sorts, they exploit the fixed structure of the inputs.

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贪生不怕死
6楼-- · 2019-01-03 10:38

Counting sort: http://en.wikipedia.org/wiki/Counting_sort if your integers are fairly small. Radix sort if you have bigger numbers (this is basically a generalization of counting sort, or an optimization for bigger numbers if you will): http://en.wikipedia.org/wiki/Radix_sort

There is also bucket sort: http://en.wikipedia.org/wiki/Bucket_sort

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Viruses.
7楼-- · 2019-01-03 10:38

These hardware-based sorting algorithms:

A Comparison-Free Sorting Algorithm
Sorting Binary Numbers in Hardware - A Novel Algorithm and its Implementation

Laser Domino Sorting Algorithm - a thought experiment by me based on Counting Sort with an intention to achieve O(n) time complexity over Counting Sort's O(n + k).

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