I have a table like this,
> head(dt2)
Weight Height Fitted interval limit value
1 65.6 174.0 71.91200 pred lwr 53.73165
2 80.7 193.5 91.63237 pred lwr 73.33198
3 72.6 186.5 84.55326 pred lwr 66.31751
4 78.8 187.2 85.26117 pred lwr 67.02004
5 74.8 181.5 79.49675 pred lwr 61.29244
6 86.4 184.0 82.02501 pred lwr 63.80652
I want it to have like this,
> head(reshape2::dcast(dt2,
Weight + Height + Fitted + interval ~ limit,
fun.aggregate = mean))
Weight Height Fitted interval lwr upr
1 42.0 153.4 51.07920 conf 49.15463 53.00376
2 42.0 153.4 51.07920 pred 32.82122 69.33717
3 43.2 160.0 57.75378 conf 56.35240 59.15516
4 43.2 160.0 57.75378 pred 39.54352 75.96404
5 44.8 149.5 47.13512 conf 44.87642 49.39382
6 44.8 149.5 47.13512 pred 28.83891 65.43133
But using tidyr::spread
, How can I do that?
I was using,
> tidyr::spread(dt2, limit, value)
But getting the error,
Error: Duplicate identifiers for rows (1052, 1056), (238, 242), (1209, 1218), (395, 404), (839, 1170), (25, 356), (1173, 1203, 1215), (359, 389, 401), (1001, 1200), (187, 386), (906, 907), (92, 93), (930, 1144), (116, 330), (958, 1171), (144, 357), (902, 1018), (88, 204), (960, 1008), (146, 194), (1459, 1463), (645, 649), (1616, 1625), (802, 811), (1246, 1577), (432, 763), (1580, 1610, 1622), (766, 796, 808), (1408, 1607), (594, 793), (1313, 1314), (499, 500), (1337, 1551), (523, 737), (1365, 1578), (551, 764), (1309, 1425), (495, 611), (1367, 1415), (553, 601)
Random 10 Rows::
> dt[sample(nrow(dt), 10), ]
Weight Height Fitted interval limit value
1253 52.2 162.5 60.28203 conf upr 61.51087
426 49.1 158.8 56.54022 pred upr 74.75756
1117 78.4 184.5 82.53066 conf lwr 80.98778
1171 85.9 166.4 64.22611 conf lwr 63.21254
948 61.4 177.8 75.75494 conf lwr 74.66393
384 90.9 172.7 70.59731 pred lwr 52.41828
289 75.9 172.7 70.59731 pred lwr 52.41828
3 44.8 149.5 47.13512 pred lwr 28.83891
774 87.3 182.9 80.91258 pred upr 99.12445
772 86.4 175.3 73.22669 pred upr 91.40919
Let's say you were starting with data that looked like this:
Notice the duplication in rows 5 and 6 of the grouping columns (1 to 5). This is essentially what "tidyr" is telling you. The first row and fifth are duplicates, as are the second and sixth.
As suggested by @Jaap, the solution is to first "summarise" the data. Since "tidyr" is only for reshaping data (unlike "reshape2", which aggregated and reshaped), you need to perform the aggregation with "dplyr" before you change the data form. Here, I've done that with
summarise
for the "value" column.If you stopped the execution at the
summarise
step, you would find that our original 6-row dataset had "shrunk" to 4 rows. Now,spread
would work as expected.This matches the expected output from
dcast
withfun.aggregate = mean
.Sample data:
Here are
data.table
alternatives todplyr
. Usemydf
from Ananda's answer.First, you can use
by
to compute the mean by each limit.If this
limit == ...
looks too much hard coding, you can first aggregate into a long format, thenspread
. This works because once you aggregate, there is no duplicate.Both gets you