Python Celery - How to call celery tasks inside ot

2019-02-07 07:21发布

I'm calling a task within a tasks in Django-Celery

Here are my tasks.

@shared_task
def post_notification(data,url):
    url = "http://posttestserver.com/data/?dir=praful" # when in production, remove this line.
    headers = {'content-type': 'application/json'}
    requests.post(url, data=json.dumps(data), headers=headers)


@shared_task
def shipment_server(data,notification_type):
    notification_obj = Notification.objects.get(name = notification_type)
    server_list = ServerNotificationMapping.objects.filter(notification_name=notification_obj)

    for server in server_list:
        task = post_notification.delay(data,server.server_id.url)
        print task.status # it prints 'Nonetype' has no attribute id

How can I call a task within a task? I read somewhere it can be done using group, but I'm not able to form the correct syntax. How do I do it?

I tried this

for server in server_list:
    task = group(post_notification.s(data, server.server_id.url))().get()
    print task.status

Throws a warning saying

TxIsolationWarning: Polling results w│                                                                        
ith transaction isolation level repeatable-read within the same transacti│                                                                        
on may give outdated results. Be sure to commit the transaction for each │                                                                        
poll iteration.                                                          │                                                                        
  'Polling results with transaction isolation level '

Dont know what it is!!!

How do I solve my problem?

3条回答
▲ chillily
2楼-- · 2019-02-07 07:37

You are right, because each task in you for loop will be overwrite task variable.

You can try celery.group like

from celery import group

and

@shared_task
def shipment_server(data,notification_type):
    notification_obj = Notification.objects.get(name = notification_type)
    server_list = ServerNotificationMapping.objects.filter(notification_name=notification_obj)


    tasks = [post_notification.s(data, server.server_id.url) for server in server_list]
    results = group(tasks)()
    print results.get() # results.status() what ever you want
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Deceive 欺骗
3楼-- · 2019-02-07 07:59

This should work:

celery.current_app.send_task('mymodel.tasks.mytask', args=[arg1, arg2, arg3])
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Explosion°爆炸
4楼-- · 2019-02-07 07:59

you can call task from a task using delay function

from app.tasks import celery_add_task
    celery_add_task.apply_async(args=[task_name]) 

... it will work

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