Multi-dimensional arrays in Bash

2019-01-03 09:46发布

I am planning a script to manage some pieces of my Linux systems and am at the point of deciding if I want to use or .

I would prefer to do this as a Bash script simply because the commands are easier, but the real deciding factor is configuration. I need to be able to store a multi-dimensional array in the configuration file to tell the script what to do with itself. Storing simple key=value pairs in config files is easy enough with bash, but the only way I can think of to do a multi-dimensional array is a two layer parsing engine, something like

array=&d1|v1;v2;v3&d2|v1;v2;v3

but the marshall/unmarshall code could get to be a bear and its far from user friendly for the next poor sap that has to administer this. If i can't do this easily in bash i will simply write the configs to an xml file and write the script in python.

Is there an easy way to do this in bash?

thanks everyone.

11条回答
Ridiculous、
2楼-- · 2019-01-03 09:55

Expanding on Paul's answer - here's my version of working with associative sub-arrays in bash:

declare -A SUB_1=(["name1key"]="name1val" ["name2key"]="name2val")
declare -A SUB_2=(["name3key"]="name3val" ["name4key"]="name4val")
STRING_1="string1val"
STRING_2="string2val"
MAIN_ARRAY=(
  "${SUB_1[*]}"
  "${SUB_2[*]}"
  "${STRING_1}"
  "${STRING_2}"
)
echo "COUNT: " ${#MAIN_ARRAY[@]}
for key in ${!MAIN_ARRAY[@]}; do
    IFS=' ' read -a val <<< ${MAIN_ARRAY[$key]}
    echo "VALUE: " ${val[@]}
    if [[ ${#val[@]} -gt 1 ]]; then
        for subkey in ${!val[@]}; do
            subval=${val[$subkey]}
            echo "SUBVALUE: " ${subval}
        done
    fi
done

It works with mixed values in the main array - strings/arrays/assoc. arrays

The key here is to wrap the subarrays in single quotes and use * instead of @ when storing a subarray inside the main array so it would get stored as a single, space separated string: "${SUB_1[*]}"

Then it makes it easy to parse an array out of that when looping through values with IFS=' ' read -a val <<< ${MAIN_ARRAY[$key]}

The code above outputs:

COUNT:  4
VALUE:  name1val name2val
SUBVALUE:  name1val
SUBVALUE:  name2val
VALUE:  name4val name3val
SUBVALUE:  name4val
SUBVALUE:  name3val
VALUE:  string1val
VALUE:  string2val
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我欲成王,谁敢阻挡
3楼-- · 2019-01-03 09:55
echo "Enter no of terms"
read count
for i in $(seq 1 $count)
do
  t=` expr $i - 1 `
  for j in $(seq $t -1 0)
  do
    echo -n " "
  done
  j=` expr $count + 1 `
  x=` expr $j - $i `
  for k in $(seq 1 $x)
  do
    echo -n "* "
  done
  echo ""
done
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该账号已被封号
4楼-- · 2019-01-03 09:56

Bash doesn't have multi-dimensional array. But you can simulate a somewhat similar effect with associative arrays. The following is an example of associative array pretending to be used as multi-dimensional array:

declare -A arr
arr[0,0]=0
arr[0,1]=1
arr[1,0]=2
arr[1,1]=3
echo "${arr[0,0]} ${arr[0,1]}" # will print 0 1

If you don't declare the array as associative (with -A), the above won't work. For example, if you omit the declare -A arr line, the echo will print 2 3 instead of 0 1, because 0,0, 1,0 and such will be taken as arithmetic expression and evaluated to 0 (the value to the right of the comma operator).

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Viruses.
5楼-- · 2019-01-03 10:01

I do this using associative arrays since bash 4 and setting IFS to a value that can be defined manually.

The purpose of this approach is to have arrays as values of associative array keys.

In order to set IFS back to default just unset it.

  • unset IFS

This is an example:

#!/bin/bash

set -euo pipefail

# used as value in asscciative array
test=(
  "x3:x4:x5"
)
# associative array
declare -A wow=(
  ["1"]=$test
  ["2"]=$test
)
echo "default IFS"
for w in ${wow[@]}; do
  echo "  $w"
done

IFS=:
echo "IFS=:"
for w in ${wow[@]}; do
  for t in $w; do
    echo "  $t"
  done
done
echo -e "\n or\n"
for w in ${!wow[@]}
do
  echo "  $w"
  for t in ${wow[$w]}
  do
    echo "    $t"
  done
done

unset IFS
unset w
unset t
unset wow
unset test

The output of the script below is:

default IFS
  x3:x4:x5
  x3:x4:x5
IFS=:
  x3
  x4
  x5
  x3
  x4
  x5

 or

  1
    x3
    x4
    x5
  2
    x3
    x4
    x5
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仙女界的扛把子
6楼-- · 2019-01-03 10:02

After a lot of trial and error i actually find the best, clearest and easiest multidimensional array on bash is to use a regular var. Yep.

Advantages: You don't have to loop through a big array, you can just echo "$var" and use grep/awk/sed. It's easy and clear and you can have as many columns as you like.

Example:

$ var=$(echo -e 'kris hansen oslo\nthomas jonson peru\nbibi abu johnsonville\njohnny lipp peru')

$ echo "$var"
kris hansen oslo
thomas johnson peru
bibi abu johnsonville
johnny lipp peru

If you want to find everyone in peru

$ echo "$var" | grep peru
thomas johnson peru
johnny lipp peru

Only grep(sed) in the third field

$ echo "$var" | sed -n -E '/(.+) (.+) peru/p'
thomas johnson peru
johnny lipp peru

If you only want x field

$ echo "$var" | awk '{print $2}'
hansen
johnson
abu
johnny

Everyone in peru that's called thomas and just return his lastname

$ echo "$var" |grep peru|grep thomas|awk '{print $2}'
johnson

Any query you can think of... supereasy.

To change an item:

$ var=$(echo "$var"|sed "s/thomas/pete/")

To delete a row that contains "x"

$ var=$(echo "$var"|sed "/thomas/d")

To change another field in the same row based on a value from another item

$ var=$(echo "$var"|sed -E "s/(thomas) (.+) (.+)/\1 test \3/")
$ echo "$var"
kris hansen oslo                                                                                                                                             
thomas test peru                                                                                                                                          
bibi abu johnsonville
johnny lipp peru

Of course looping works too if you want to do that

$ for i in "$var"; do echo "$i"; done
kris hansen oslo
thomas jonson peru
bibi abu johnsonville
johnny lipp peru

The only gotcha iv'e found with this is that you must always quote the var(in the example; both var and i) or things will look like this

$ for i in "$var"; do echo $i; done
kris hansen oslo thomas jonson peru bibi abu johnsonville johnny lipp peru

and someone will undoubtedly say it won't work if you have spaces in your input, however that can be fixed by using another delimeter in your input, eg(using an utf8 char now to emphasize that you can choose something your input won't contain, but you can choose whatever ofc):

$ var=$(echo -e 'field one☥field two hello☥field three yes moin\nfield 1☥field 2☥field 3 dsdds aq')

$ for i in "$var"; do echo "$i"; done
field one☥field two hello☥field three yes moin
field 1☥field 2☥field 3 dsdds aq

$ echo "$var" | awk -F '☥' '{print $3}'
field three yes moin
field 3 dsdds aq

$ var=$(echo "$var"|sed -E "s/(field one)☥(.+)☥(.+)/\1☥test☥\3/")
$ echo "$var"
field one☥test☥field three yes moin
field 1☥field 2☥field 3 dsdds aq

If you want to store newlines in your input, you could convert the newline to something else before input and convert it back again on output(or don't use bash...). Enjoy!

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爷、活的狠高调
7楼-- · 2019-01-03 10:08

Bash does not support multidimensional arrays, nor hashes, and it seems that you want a hash that values are arrays. This solution is not very beautiful, a solution with an xml file should be better :

array=('d1=(v1 v2 v3)' 'd2=(v1 v2 v3)')
for elt in "${array[@]}";do eval $elt;done
echo "d1 ${#d1[@]} ${d1[@]}"
echo "d2 ${#d2[@]} ${d2[@]}"
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