How do I pipe a subprocess call to a text file?

Question

subprocess.call(["/home/myuser/run.sh", "/tmp/ad_xml",  "/tmp/video_xml"])

RIght now I have a script that I run. When I run it and it hits this line, it starts printing stuff because run.sh has prints in it.

How do I pipe this to a text file also? (And also print, if possible)

Answer 1

The options for popen can be used in call

args, 
bufsize=0, 
executable=None, 
stdin=None, 
stdout=None, 
stderr=None, 
preexec_fn=None, 
close_fds=False, 
shell=False, 
cwd=None, 
env=None, 
universal_newlines=False, 
startupinfo=None, 
creationflags=0

So...

subprocess.call(["/home/myuser/run.sh", "/tmp/ad_xml",  "/tmp/video_xml"], stdout=myoutput)

Then you can do what you want with myoutput (which would need to be a file btw).

Also, you can do something closer to a piped output like this.

dmesg | grep hda

would be:

p1 = Popen(["dmesg"], stdout=PIPE)
p2 = Popen(["grep", "hda"], stdin=p1.stdout, stdout=PIPE)
output = p2.communicate()[0]

There's plenty of lovely, useful info on the python manual page.

Answer 2

If you want to write the output to a file you can use the stdout-argument of subprocess.call.

It takes None, subprocess.PIPE, a file object or a file descriptor. The first is the default, stdout is inherited from the parent (your script). The second allows you to pipe from one command/process to another. The third and fourth are what you want, to have the output written to a file.

You need to open a file with something like open and pass the object or file descriptor integer to call:

f = open("blah.txt", "w")
subprocess.call(["/home/myuser/run.sh", "/tmp/ad_xml",  "/tmp/video_xml"], stdout=f)

I'm guessing any valid file-like object would work, like a socket (gasp :)), but I've never tried.

As marcog mentions in the comments you might want to redirect stderr as well, you can redirect this to the same location as stdout with stderr=subprocess.STDOUT. Any of the above mentioned values works as well, you can redirect to different places.