Generating random numbers in Objective-C

2018-12-31 04:41发布

I'm a Java head mainly, and I want a way to generate a pseudo-random number between 0 and 74. In Java I would use the method:

Random.nextInt(74)

I'm not interested in a discussion about seeds or true randomness, just how you accomplish the same task in Objective-C. I've scoured Google, and there just seems to be lots of different and conflicting bits of information.

13条回答
后来的你喜欢了谁
2楼-- · 2018-12-31 04:41

Use the arc4random_uniform(upper_bound) function to generate a random number within a range. The following will generate a number between 0 and 73 inclusive.

arc4random_uniform(74)

arc4random_uniform(upper_bound) avoids modulo bias as described in the man page:

arc4random_uniform() will return a uniformly distributed random number less than upper_bound. arc4random_uniform() is recommended over constructions like ``arc4random() % upper_bound'' as it avoids "modulo bias" when the upper bound is not a power of two.

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唯独是你
3楼-- · 2018-12-31 04:41

I wrote my own random number utility class just so that I would have something that functioned a bit more like Math.random() in Java. It has just two functions, and it's all made in C.

Header file:

//Random.h
void initRandomSeed(long firstSeed);
float nextRandomFloat();

Implementation file:

//Random.m
static unsigned long seed;

void initRandomSeed(long firstSeed)
{ 
    seed = firstSeed;
}

float nextRandomFloat()
{
    return (((seed= 1664525*seed + 1013904223)>>16) / (float)0x10000);
}

It's a pretty classic way of generating pseudo-randoms. In my app delegate I call:

#import "Random.h"

- (void)applicationDidFinishLaunching:(UIApplication *)application
{
    initRandomSeed( (long) [[NSDate date] timeIntervalSince1970] );
    //Do other initialization junk.
}

Then later I just say:

float myRandomNumber = nextRandomFloat() * 74;

Note that this method returns a random number between 0.0f (inclusive) and 1.0f (exclusive).

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一个人的天荒地老
4楼-- · 2018-12-31 04:43

There are some great, articulate answers already, but the question asks for a random number between 0 and 74. Use:

arc4random_uniform(75)

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弹指情弦暗扣
5楼-- · 2018-12-31 04:43

For game dev use random() to generate randoms. Probably at least 5x faster than using arc4random(). Modulo bias is not an issue, especially for games, when generating randoms using the full range of random(). Be sure to seed first. Call srandomdev() in AppDelegate. Here's some helper functions:

static inline int random_range(int low, int high){ return (random()%(high-low+1))+low;}
static inline CGFloat frandom(){ return (CGFloat)random()/UINT32_C(0x7FFFFFFF);}
static inline CGFloat frandom_range(CGFloat low, CGFloat high){ return (high-low)*frandom()+low;}
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还给你的自由
6楼-- · 2018-12-31 04:44

Same as C, you would do

#include <time.h>
#include <stdlib.h>
...
srand(time(NULL));
int r = rand() % 74;

(assuming you meant including 0 but excluding 74, which is what your Java example does)

Edit: Feel free to substitute random() or arc4random() for rand() (which is, as others have pointed out, quite sucky).

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不流泪的眼
7楼-- · 2018-12-31 04:47

This will give you a floating point number between 0 and 47

float low_bound = 0;      
float high_bound = 47;
float rndValue = (((float)arc4random()/0x100000000)*(high_bound-low_bound)+low_bound);

Or just simply

float rndValue = (((float)arc4random()/0x100000000)*47);

Both lower and upper bound can be negative as well. The example code below gives you a random number between -35.76 and +12.09

float low_bound = -35.76;      
float high_bound = 12.09;
float rndValue = (((float)arc4random()/0x100000000)*(high_bound-low_bound)+low_bound);

Convert result to a rounder Integer value:

int intRndValue = (int)(rndValue + 0.5);
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