What's the reason I can't create generic a

2018-12-31 04:03发布

What's the reason Java doesn't allow us to do

private T[] elements = new T[initialCapacity];

I could understand .NET didn't allow us to do that, as in .NET you have value types that at run-time can have different sizes, but in Java all kinds of T will be object references, thus having the same size (correct me if I'm wrong).

What is the reason?

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梦寄多情
2楼-- · 2018-12-31 04:59

It's because Java's arrays (unlike generics) contain, at runtime, information about its component type. So you must know the component type when you create the array. Since you don't know what T is at runtime, you can't create the array.

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人间绝色
3楼-- · 2018-12-31 04:59

From Oracle tutorial:

You cannot create arrays of parameterized types. For example, the following code does not compile:

List<Integer>[] arrayOfLists = new List<Integer>[2];  // compile-time error

The following code illustrates what happens when different types are inserted into an array:

Object[] strings = new String[2];
strings[0] = "hi";   // OK
strings[1] = 100;    // An ArrayStoreException is thrown.

If you try the same thing with a generic list, there would be a problem:

Object[] stringLists = new List<String>[];  // compiler error, but pretend it's allowed
stringLists[0] = new ArrayList<String>();   // OK
stringLists[1] = new ArrayList<Integer>();  // An ArrayStoreException should be thrown,
                                            // but the runtime can't detect it.

If arrays of parameterized lists were allowed, the previous code would fail to throw the desired ArrayStoreException.

To me, it sounds very weak. I think that anybody with a sufficient understanding of generics, would be perfectly fine, and even expect, that the ArrayStoredException is not thrown in such case.

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