Sort array of objects by their NSDate property [du

2019-02-02 22:07发布

Possible Duplicate:
How to sort an NSMutableArray with custom objects in it?

How does one sort an array of objects by accessing their NSDate properties?

I know one can use [mutableArray sortUsingSelector:@selector(compare:)]; on an array of dates, but how does one do it by accessing a NSDate property on each element in the array, sorting the objects by earliest date to latest date?

5条回答
别忘想泡老子
2楼-- · 2019-02-02 22:49

You can use:

   NSArray *sortedArray = [mutableArray sortedArrayUsingComparator:^NSComparisonResult(id a, id b) {
        NSDate *first = [(Person*)a birthDate];
        NSDate *second = [(Person*)b birthDate];
        return [first compare:second];
    }];

Or see this link

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Melony?
3楼-- · 2019-02-02 22:50

You can override the compare method in your custom class so that it compares two objects of your custom class and returns the appropriate NSComparisonResult according to the dates on the objects.

Eg:

-(NSComparisonResult)compare:(YourClass*)otherObject
{
   return [self.date compare:otherObject.date];
}
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Root(大扎)
4楼-- · 2019-02-02 22:52
    NSSortDescriptor* sortByDate = [NSSortDescriptor sortDescriptorWithKey:@"nsdatepropertyname" ascending:YES];
    [mutableArray sortUsingDescriptors:[NSArray arrayWithObject:sortByDate]];
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smile是对你的礼貌
5楼-- · 2019-02-02 23:00

There is a method called -[NSArray sortedArrayUsingComparator:]. It takes a block in which you can implement any comparison you see fit for your objects.

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啃猪蹄的小仙女
6楼-- · 2019-02-02 23:03

Thanks for all the answers, I came across this answer that solved my problem.Check NSGod's answer

Here is the code thanks to user: NSGod:

NSSortDescriptor *dateDescriptor = [NSSortDescriptor
                                 sortDescriptorWithKey:@"startDateTime" 
                                             ascending:YES];
NSArray *sortDescriptors = [NSArray arrayWithObject:dateDescriptor];
NSArray *sortedEventArray = [nodeEventArray
     sortedArrayUsingDescriptors:sortDescriptors];
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