No matching global declaration available for the v

2019-02-02 02:12发布

Background

Validate an XML document using a schema.

Problem

The simplest form of the problem is shown in two files.

XML Document

<?xml version="1.0"?>

<recipe
  xmlns:r="http://www.namespace.org/recipe">

<r:description>
  <r:title>sugar cookies</r:title>
</r:description>

</recipe>

XSD Document

<?xml version="1.0" encoding="utf-8"?>
<xsd:schema
   version="1.0"
   xmlns:xsd="http://www.w3.org/2001/XMLSchema"
   xmlns:r="http://www.namespace.org/recipe">

  <xsd:complexType name="recipe">
    <xsd:choice>
      <xsd:element name="description" type="descriptionType"
        minOccurs="1" maxOccurs="1" />
    </xsd:choice>
  </xsd:complexType>

  <xsd:complexType name="descriptionType">
    <xsd:all>
      <xsd:element name="title">
        <xsd:simpleType>
          <xsd:restriction base="xsd:string">
            <xsd:minLength value="5" />
            <xsd:maxLength value="55" />
          </xsd:restriction>
        </xsd:simpleType>
      </xsd:element>
    </xsd:all>
  </xsd:complexType>
</xsd:schema>

Error

The full error message from xmllint:

file.xml:4: element recipe: Schemas validity error : Element 'recipe': No matching global declaration available for the validation root.

Question

What is the correct syntax (or what schema attributes are missing) to ensure that the given schema can be used to successfully validate the given XML document?

标签: xml xsd xmllint
3条回答
做个烂人
2楼-- · 2019-02-02 02:40

In my practice, I got the No matching global declaration available for the validation root in two cases:

  • If XSD does not contain an <xsd:element name="recipe" .../> explained in @aravind-r-yarram's answer.
  • If <recipe/> in XML does not contain an xmlns attribute. In such case adding the xmlns will help:

    <recipe xmlns="http://www.namespace.org/recipe">
        ...
    </recipe>
    
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戒情不戒烟
3楼-- · 2019-02-02 03:04

You need to change your XML instance. Your current one says that it is looking for a type called description in the namespace http://www.namespace.org/recipe. However, the only types exposed in that namespace are called recipe and descriptionType.

So either define a type called description in the XSD schema, or change your instance so you are referencing the recipe type correctly:

<?xml version="1.0" encoding="utf-8"?>
<r:recipe
  xmlns:r="http://www.namespace.org/recipe">
  <description>
    <title>sugar cookies</title>
  </description>
</r:recipe>
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老娘就宠你
4楼-- · 2019-02-02 03:04

Only global element definitions can be used as root elements. Your schema only has complex types and hence the error. Change the <xsd:complexType name="recipe"> to

<xsd:element name="recipe">
  <xsd:complexType>
    <xsd:choice>
      <xsd:element name="description" type="descriptionType"
        minOccurs="1" maxOccurs="1" />
    </xsd:choice>
  </xsd:complexType>
</xsd:element>

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