How do I get ASP.NET Web API to return JSON instea

2018-12-31 03:44发布

Using the newer ASP.NET Web API, in Chrome I am seeing XML - how can I change it to request JSON so I can view it in the browser? I do believe it is just part of the request headers, am I correct in that?

29条回答
浮光初槿花落
2楼-- · 2018-12-31 04:31

You can use as below:

GlobalConfiguration.Configuration.Formatters.Clear();
GlobalConfiguration.Configuration.Formatters.Add(new JsonMediaTypeFormatter());
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路过你的时光
3楼-- · 2018-12-31 04:33

Returning the correct format is done by the media-type formatter. As others mentioned, you can do this in the WebApiConfig class:

public static class WebApiConfig
{
    public static void Register(HttpConfiguration config)
    {
        ...

        // Configure Web API to return JSON
        config.Formatters.JsonFormatter
        .SupportedMediaTypes.Add(new System.Net.Http.Headers.MediaTypeHeaderValue("text/html"));

        ...
    }
}

For more, check:

In case your actions are returning XML (which is the case by default) and you need just a specific method to return JSON, you can then use an ActionFilterAttribute and apply it to that specific action.

Filter attribute:

public class JsonOutputAttribute : ActionFilterAttribute
{
    public override void OnActionExecuted(HttpActionExecutedContext actionExecutedContext)
    {
        ObjectContent content = actionExecutedContext.Response.Content as ObjectContent;
        var value = content.Value;
        Type targetType = actionExecutedContext.Response.Content.GetType().GetGenericArguments()[0];

        var httpResponseMsg = new HttpResponseMessage
        {
            StatusCode = HttpStatusCode.OK,
            RequestMessage = actionExecutedContext.Request,
            Content = new ObjectContent(targetType, value, new JsonMediaTypeFormatter(), (string)null)
        };

        actionExecutedContext.Response = httpResponseMsg;
        base.OnActionExecuted(actionExecutedContext);
    }
}

Applying to action:

[JsonOutput]
public IEnumerable<Person> GetPersons()
{
    return _repository.AllPersons(); // the returned output will be in JSON
}

Note that you can omit the word Attribute on the action decoration and use just [JsonOutput] instead of [JsonOutputAttribute].

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无色无味的生活
4楼-- · 2018-12-31 04:35

It's unclear to me why there is all of this complexity in the answer. Sure there are lots of ways you can do this, with QueryStrings, headers and options... but what I believe to be the best practice is simple. You request a plain URL (ex: http://yourstartup.com/api/cars) and in return you get JSON. You get JSON with the proper response header:

Content-Type: application/json

In looking for an answer to this very same question, I found this thread, and had to keep going because this accepted answer doesn't work exactly. I did find an answer which I feel is just too simple not to be the best one:

Set the default WebAPI formatter

I'll add my tip here as well.

WebApiConfig.cs

namespace com.yourstartup
{
  using ...;
  using System.Net.Http.Formatting;
  ...
  config.Formatters.Clear(); //because there are defaults of XML..
  config.Formatters.Add(new JsonMediaTypeFormatter());
}

I do have a question of where the defaults (at least the ones I am seeing) come from. Are they .NET defaults, or perhaps created somewhere else (by someone else on my project). Anways, hope this helps.

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其实,你不懂
5楼-- · 2018-12-31 04:36

If you do this in the WebApiConfig you will get JSON by default, but it will still allow you to return XML if you pass text/xml as the request Accept header

public static class WebApiConfig
{
    public static void Register(HttpConfiguration config)
    {
        config.Routes.MapHttpRoute(
            name: "DefaultApi",
            routeTemplate: "api/{controller}/{id}",
            defaults: new { id = RouteParameter.Optional }
        );

        var appXmlType = config.Formatters.XmlFormatter.SupportedMediaTypes.FirstOrDefault(t => t.MediaType == "application/xml");
        config.Formatters.XmlFormatter.SupportedMediaTypes.Remove(appXmlType);
    }
}

If you are not using the MVC project type and therefore did not have this class to begin with, see this answer for details on how to incorporate it.

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残风、尘缘若梦
6楼-- · 2018-12-31 04:37

Here is a solution similar to jayson.centeno's and other answers, but using the built-in extension from System.Net.Http.Formatting.

public static void Register(HttpConfiguration config)
{
    // add support for the 'format' query param
    // cref: http://blogs.msdn.com/b/hongyes/archive/2012/09/02/support-format-in-asp-net-web-api.aspx
    config.Formatters.JsonFormatter.AddQueryStringMapping("$format", "json", "application/json");
    config.Formatters.XmlFormatter.AddQueryStringMapping("$format", "xml", "application/xml");

    // ... additional configuration
 }

The solution was primarily geared toward supporting $format for OData in the early releases of WebApi, but it also applies to the non-OData implementation, and returns the Content-Type: application/json; charset=utf-8 header in the response.

It allows you to tack &$format=json or &$format=xml to the end of your uri when testing with a browser. It does not interfere with other expected behavior when using a non-browser client where you can set your own headers.

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泛滥B
7楼-- · 2018-12-31 04:37

From MSDN Building a Single Page Application with ASP.NET and AngularJS (about 41 mins in).

public static class WebApiConfig
{
    public static void Register(HttpConfiguration config)
    {
        // ... possible routing etc.

        // Setup to return json and camelcase it!
        var formatter = GlobalConfiguration.Configuration.Formatters.JsonFormatter;
        formatter.SerializerSettings.ContractResolver =
            new Newtonsoft.Json.Serialization.CamelCasePropertyNamesContractResolver();
    }

It should be current, I tried it and it worked.

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