I am attempting to override the <<
operator for a class. The purpose is basically to implement a toString()
like behavior for my class, so that sending it to cout
will produce useful output. Using a dummy example, I have the code below. When I attempt to compile, I get the foollowing error:
$ g++ main.cpp Rectangle.cpp
/tmp/ccWs2n6V.o: In function `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)':
Rectangle.cpp:(.text+0x0): multiple definition of `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)'
/tmp/ccLU2LLE.o:main.cpp:(.text+0x0): first defined here
I can't figure out why this is happening. my code is below:
Rectangle.h:
#include <iostream>
using namespace std;
class CRectangle {
private:
int x, y;
friend ostream& operator<<(ostream& out, const CRectangle& r);
public:
void set_values (int,int);
int area ();
};
ostream& operator<<(ostream& out, const CRectangle& r){
return out << "Rectangle: " << r.x << ", " << r.y;
}
Rectangle.cpp:
#include "Rectangle.h"
using namespace std;
int CRectangle::area (){
return x*y;
}
void CRectangle::set_values (int a, int b) {
x = a;
y = b;
}
main.cpp:
#include <iostream>
#include "Rectangle.h"
using namespace std;
int main () {
CRectangle rect;
rect.set_values (3,4);
cout << "area: " << rect.area();
return 0;
}
You are putting the definition of a function in a
.h
file, which means that it will appear in every translation unit, violating the One Definition Rule (=> you definedoperator<<
in every object module, so the linker doesn't know which is "the right one").You can either:
rectangle.cpp
operator<<
inline
-inline
functions are allowed to be defined more than once, as long as all the definitions are identical.(Also, you should use header guards in your includes.)
You're breaking the one definition rule. A quick-fix is:
Others are:
Rectangle.cpp
file..
Bonus:
using namespace std;
from the header.