Concatenating Variable Names in C?

2019-01-03 03:17发布

Is it possible to concatenate variable names in C? Specifically, I have a struct that contains 6 similar variables in it called class1, class2, class3, etc.

I want to run through a for loop to assign each variable a value, but I can't see how to do it without somehow concatenating the variable name with the value of the for loop counter.

How else could I do this?

5条回答
你好瞎i
2楼-- · 2019-01-03 03:59

When you find yourself adding an integer suffix to variable names, think I should have used an array.

struct mystruct {
    int class[6];
};

int main(void) {
    struct mystruct s;
    int i;
    for (i = 0; i < 6; ++i) {
        s.class[i] = 1000 + i;
    }

    return 0;
}

Note: A C++ compiler will barf at this because of class. You will need to figure out a different name for that field if you plan to compile this code as C++.

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你好瞎i
3楼-- · 2019-01-03 03:59

There are dynamic languages where you can do this sort of thing - C is not one of these languages. I agree with Sinan - arrays or STL vectors are the way to go.

As a thought experiment - what would happen if you have 100,000 of these variables? Would you have 100,000 lines of code to initialise them?

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forever°为你锁心
4楼-- · 2019-01-03 03:59

What you could also do, is write an implementation of a hash map. Since the set of keys (that would be like variable names) of the hash map does not change over time, for each hash map you could keep an array of its keys for iterating efficiently. But that would be a total (crazy) overkill, especially in C ;)

Pretty much anything is possible in C, it's a great language to learn :)

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beautiful°
5楼-- · 2019-01-03 04:12

The C preprocessor can concatenate symbols, but have you considered just using an array?

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对你真心纯属浪费
6楼-- · 2019-01-03 04:18

perhaps the CERT-C secure coding rule PRE05-C 'Understand macro replacement when concatenating tokens or performing stringification' could help you. For deep details have a look at this link: https://www.securecoding.cert.org/confluence/display/seccode/PRE05-C.+Understand+macro+replacement+when+concatenating+tokens+or+performing+stringification.

For short, define first a macro JOIN_AGAIN(x,y) (x##y) and then JOIN(x,y) JOIN_AGAIN(x,y) The JOIN_AGAIN macro allows to expand the value of the loop couner which will be concatenated to the var name.

Cheers Pierre Bui

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